Accenture
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Numerical Ability
Permutation and Combination
At an international conference, 100 delegates spoke English, 40 spoke French, and 20 spoke both English and French. How many delegates could speak at least one of these two languages?
Read Solution (Total 12)
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- n(a)+n(b)-n(a and b)=n(a or b)
100+40-20
=120 - 10 years agoHelpfull: Yes(15) No(3)
- no. of delegates spoke only english=80
no. of delegates spoke only french=20
no. of delegates spoke both=20
therefore no. of delegates spoke at least one of the language=(80+20+20)=120 - 10 years agoHelpfull: Yes(5) No(2)
- NUMBER of delegates spoke BOTH=20
NUMBER of delegates spoke only ENGLISH=100-20=80
NUMBER of delegates spoke only FRENCH=40-20=20
THEREFORE,
120 ( 80+20+20 ) Delegates could speak at least one of these two languages.. - 10 years agoHelpfull: Yes(5) No(0)
- atlest=100+40-20
120 - 10 years agoHelpfull: Yes(3) No(1)
- only E=80
only F=20
both=20
120 - 10 years agoHelpfull: Yes(1) No(1)
- n(a)+n(b)-n(a and b)=n(a or b)
100+40-20
=120 - 10 years agoHelpfull: Yes(1) No(0)
- 120=ans=100+40-20=120
- 10 years agoHelpfull: Yes(1) No(0)
- (a uinon b) = a + b -(a intersection b)
(a uinon b) = 100 + 40 - (20)
(a uinon b) = 120 - 10 years agoHelpfull: Yes(0) No(0)
- ) here English=100 French=40 and Both=20…if that Both speakers are in 100+40…. Then the answer will be 100+40-20=120.
Note:If that both speakers are separate speakers…then the answer will be 100+40=140
- 10 years agoHelpfull: Yes(0) No(0)
- ans= 120 delegates
- 9 years agoHelpfull: Yes(0) No(0)
- 120 delegates........By Venn Diagrams
- 8 years agoHelpfull: Yes(0) No(0)
- P(E or F)=P(E)+P(F)-(E and F)
=100+40-20
=120 - 5 years agoHelpfull: Yes(0) No(0)
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