At an international conference, 100 delegates spoke English, 40 spoke French, and 20 spoke both English and French. How many delegates could speak at least one of these two languages?

• n(a)+n(b)-n(a and b)=n(a or b)
  100+40-20
  =120
• 10 years agoHelpfull: Yes(15) No(3)
• no. of delegates spoke only english=80
  no. of delegates spoke only french=20
  no. of delegates spoke both=20
  therefore no. of delegates spoke at least one of the language=(80+20+20)=120
• 10 years agoHelpfull: Yes(5) No(2)
• NUMBER of delegates spoke BOTH=20
  NUMBER of delegates spoke only ENGLISH=100-20=80
  NUMBER of delegates spoke only FRENCH=40-20=20
  THEREFORE,
  120 ( 80+20+20 ) Delegates could speak at least one of these two languages..
• 10 years agoHelpfull: Yes(5) No(0)
• atlest=100+40-20
  
  120
• 10 years agoHelpfull: Yes(3) No(1)
• only E=80
  only F=20
  both=20
  120
• 10 years agoHelpfull: Yes(1) No(1)
• n(a)+n(b)-n(a and b)=n(a or b)
  100+40-20
  =120
• 10 years agoHelpfull: Yes(1) No(0)
• 120=ans=100+40-20=120
• 9 years agoHelpfull: Yes(1) No(0)
• (a uinon b) = a + b -(a intersection b)
  (a uinon b) = 100 + 40 - (20)
  (a uinon b) = 120
• 9 years agoHelpfull: Yes(0) No(0)
• ) here English=100 French=40 and Both=20…if that Both speakers are in 100+40…. Then the answer will be 100+40-20=120.
  Note:If that both speakers are separate speakers…then the answer will be 100+40=140
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans= 120 delegates
  
• 8 years agoHelpfull: Yes(0) No(0)
• 120 delegates........By Venn Diagrams
• 7 years agoHelpfull: Yes(0) No(0)
• P(E or F)=P(E)+P(F)-(E and F)
  =100+40-20
  =120
• 4 years agoHelpfull: Yes(0) No(0)