Elitmus
Exam
Numerical Ability
Algebra
The functions f : R -> R is defined by
F(x)= 12x + 5 if x > 1
x – 4 if x £ 1
Which of the following is false?
(a) f (0) = -4 (b) f ( -½) = -9/2
(c) f (3) = 41 (d) f (-5) = 9 (e) none of these
Read Solution (Total 7)
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- option d as -5-4 is not =9
- 10 years agoHelpfull: Yes(17) No(0)
- when x=3,f(3)=12(3)+5=41...so option c is correct
- 10 years agoHelpfull: Yes(2) No(13)
- its D
as -5-4=-9 and not 9 - 10 years agoHelpfull: Yes(2) No(0)
- Ans is option d
F(-5)= -5-4=-9 , not =9
- 10 years agoHelpfull: Yes(1) No(0)
- only option "c" is correct a b and d are wrong as x>1.so i think the question might be wrong
- 9 years agoHelpfull: Yes(0) No(2)
- option d is wrong
f(-5)=-5-4=-9 - 9 years agoHelpfull: Yes(0) No(0)
- answer : e
coz, c is not false and here given, only for x>1 but not x=0 or x - 7 years agoHelpfull: Yes(0) No(0)
Elitmus Other Question
If the relation R: A -> B where A= {1,2,3} and B={1,3,5} is defined by
R={ (x,y) : x < y , x Î A, y Î B }then
(a) R= { ( 1,3), (1,5), (2,3), (2,5), (3,5) }
(b) R= { ( 1,1), (1,5), (2,3), (3,5) }
(c) R-1 = { ( 3,1), (5,1), (3,2), (5,3) }
(d) R-1 = { ( 1,1), (5,1), (3,2), (5,3) }
(e) None of these
How many 1s in the binary representation of 512*64+255+3?
options: a)11 b)9 c)13 d) don't remember
Asked on 25th may 2014