There is a certain four digit number whose fourth digit is twice the first digit. Third digit is three more than second digit. Sum of the first and fourth digits twice the third number. What was that number ?

• 2034 and 4368 satisfy given conditions
• 15 years agoHelpfull: Yes(23) No(6)
• 8634 and 4302
• 14 years agoHelpfull: Yes(1) No(10)
• 4368
  a b 3+b 2a
  a+2a=2(3+b)
  3a-2b=6
• 10 years agoHelpfull: Yes(1) No(1)
• The first digit have only 4 choices(1,2,3,4) ,then last digit will be (2,4,6,8).Starting the iteration from 1.
  when we take 1 for first digit ,fourth will be 2.but third digit is half of sum of first and fourth so not possible.
  2,4 make sense =>2034
  3,6 rejected as sum is odd
  4,8 again make sense=> 4368
• 8 years agoHelpfull: Yes(1) No(0)
• 3036 fourth digit is twice the first digit is 6 and third digit is three more than send digit i.e 3 . first and fourt digits twice the third number
• 8 years agoHelpfull: Yes(0) No(3)
• Let the four digit number be x y z p
  Given conditions : p = 2x, z = y +3, x + p = 2z
  x + p = 2z
  x + 2x = 2 (y+3), 3x = 2y + 6, x = (2y + 6)/3
  Let us assume different numbers for y and find x. x must be a whole number
  Let y = 0, x = 2, p =4, z = 3, 2034 One possibility.
  Let y = 2, x is a fraction, Let y = 3, x =4, p=8, z = 6 4368 Another possibility.
  Let y = 4, x is a fraction, Let y = 5, x is a fraction, Let y = 6, x =6, p becomes a 2 digit number.
  Since z = y + 3, y has to be Less than three.
  A Kandaswamy
• 2 years agoHelpfull: Yes(0) No(0)