Elitmus
Exam
Numerical Ability
Geometry
PQR is an right angle triangle (where P is not the greatest angle...sth like this).QD is the angle of bisector?
IS PD>RD
(i)R is 30 degree
(ii) hypotenuse PR IS 15cm
options:
(a)Alone suff
(b)either one not suff
(c)Both Required
(d)Both not required
Answer the data suff...from set D.
Read Solution (Total 6)
-
- PD>RD Not True.
In Triangle PDQ,
If we draw the figure we find that angle QPD=60 degree. (angle R is 30 degree).
PQD=45 degree.
Therefore, DQ>PD --- (1) (side oppsite to greater angle is also greater).
IN Triangle DRQ
Similarly, angle DRQ=30 degree.
angle DQR=45 degree.
Thus, RD>DQ. ----- (2)
From (1) and (2) RD>PD... Thus (i) is sufficient to answer the question.
PD>RD is Not True.
- 10 years agoHelpfull: Yes(21) No(2)
- option a
tan R= tan 30= 1/sqrt(3)= QD/RD. so, RD= sqrt(3)*QD
tan P= tan 60= sqrt(3)= QD/PD. so, PD= QD/sqrt(3)
so, PD>RD not true
so, (i) is enough to answer - 10 years agoHelpfull: Yes(5) No(9)
- (d)Both are not sufficient to answer.it is the very right answer.
- 10 years agoHelpfull: Yes(4) No(5)
- both statement is not sufficient because perpendicular and base side value is not give, so unique ans cannot come with these information.
- 10 years agoHelpfull: Yes(2) No(3)
- option c is correct ??
- 9 years agoHelpfull: Yes(0) No(3)
- i don't know
- 4 years agoHelpfull: Yes(0) No(0)
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