What is the remainder when 132^66^33 is divided by 5?
(a) 4
(b) 3
(c) 2
(d) 1

• Ans is (D) i.e. 1
  132=130+2 i.e 130 is divisible by 5.Therefore will always leave remainder ZERO.
  Now, 2^66^33 will give us required remainder.
  Take 2^66 => 16^64 => On Dividing 16 by 5, Remainder=1
  Therefore, 1^64^33 is equals 1.
  Hence Remainder = 1
• 10 years agoHelpfull: Yes(4) No(2)
• unit digit in 132^66^33 is 4
  reminder of 132^66^33/5 is 4
• 10 years agoHelpfull: Yes(2) No(1)
• 1
  (130+2)^66^33=2^66^33
  Now 2^4% 5=1
  Therfore
  2^66^33=2^4k+r
  Calculate remainder(r) in 66^66=4k+r
  This can b done as (64+2)^66%4=2^66%4=0=r
  Hence 2^66^33=2^4k
  Putting in original
  32^32^32=2^32^32=2^4k% 5=1
  
  
• 10 years agoHelpfull: Yes(1) No(0)
• ans is 1
  (130 + 2)^66^33/5
  2^66^33/5
  1
  
  
• 10 years agoHelpfull: Yes(0) No(3)
• answer is 2 becoz when 132/5 remainder is 2
• 10 years agoHelpfull: Yes(0) No(4)
• Answer is 1... But can anyone explain in detail...
• 10 years agoHelpfull: Yes(0) No(0)
• R(132/5)=2
  so 2^66^33=132^66^33
  (2^6^10*2^6)^33
  here 2^6=64...R(64/5)=1
  (1^10*2^6)^33
  (2^6)^33
  (2^6^30*2^3)
  Again R(64/5)=1
  (1^30)*2^3
  8
  FINALLY R(8/5)=3
  so 3 is d ans
• 10 years agoHelpfull: Yes(0) No(2)