A material's cost is directly proportional to the square of its weight.When this material is broken into pieces of the weight ratio 1:2:3:5,it fetched Rs.162000( m not sure what this value was).So what is the original cost of material?
Perhaps the answer was Rs.242000

• Question was this after breaking into pieces it fetched Rs.164000,original price?
  Let original weight=x
  Cost=kw^2 (k proportionality const )
  Now material broken into ratio 1:2:3:5 so weight of individual piece is 1/11w,2/11w,3/11w,5/11w
  Cost = kw^2/121 + 4kw^2/121 + 9kw^2/121 + 25kw^2/121 =39kw^2/121
  As per ques . kw^2 - 39kw^2/121 = 164000
  Original value kw^2 would come out as 242000
• 10 years agoHelpfull: Yes(14) No(0)
• Question was typed wrng,it was like that:
  It fetched Rs.162000 less on sell after it is broken
  
• 10 years agoHelpfull: Yes(4) No(0)
• weights are 1x,2x,3x,5x
  sum of individual squares=1+4+9+25=39x^2
  as given 39x^2=162000
  x^2=4154
  Have to find original cost which is (1x+2x+3x+5x)^2=121x^2
  121x^2=121*4154
  =502634(approx)
• 10 years agoHelpfull: Yes(2) No(2)
• X^1+2X^2+3X^2+5X^2 = 162000
  39X^2=162000
  x=sqrt of 162000/39
• 10 years agoHelpfull: Yes(1) No(3)
• sum of squares of weight =total given amount
  (1x+2x+3x+5x)^2=162000
  121x^2=162000
  x^2=162000/121
  original cost=1338.84
• 10 years agoHelpfull: Yes(0) No(2)