find the output
main( )
{
static int a[ ] = {0,1,2,3,4};
int *p[ ] = {a,a+1,a+2,a+3,a+4};
int **ptr = p;
ptr++;
printf(“n %d %d %d”, ptr-p, *ptr-a, **ptr);
*ptr++;
printf(“n %d %d %d”, ptr-p, *ptr-a, **ptr);
*++ptr;
printf(“n %d %d %d”, ptr-p, *ptr-a, **ptr);
++*ptr;
printf(“n %d %d %d”, ptr-p, *ptr-a, **ptr);
}

• Ans.
  1,1,1
  2,2,2
  3,3,3
  3,4,4.
  
  from left to right we have to analyze.
  ptr=p
  ptr++ means ptr=p+1.
  s=*ptr++ means s=*ptr and ptr=p+2.
  s=*++ptr means first ptr=p+3, s=*ptr.
  s=++*ptr means first *ptr=a+3, and *ptr=*ptr+1=a+4.
  
• 10 years agoHelpfull: Yes(1) No(1)
• code error
• 10 years agoHelpfull: Yes(0) No(3)
• Go through with pointer chapter in "Exploring C" by yashwant kanetkar.
• 10 years agoHelpfull: Yes(0) No(2)
• hi muneeswaran, how error will come? pls explain
• 10 years agoHelpfull: Yes(0) No(0)