Exam Maths Puzzle Age Problem

The sum of Jane's age and Jim's age is 40 years. Jane's age 10 years from now will be 1 year less than 4 times Jim's age 6 years ago. Find their ages.

Read Solution (Total 1)

Jane=25, Jim=15

If Jane's age=x & Jim's age=y ,then
x+y=40 ---(i) &
(x+10)=4(y-6)-1, x-4y=-35 ---(ii)
On solving (i) & (ii), x=25, y=15
10 years agoHelpfull: Yes(2) No(0)

Exam Other Question

Solve
4x - y = -1
6x + 5y = 18 Please graph A (2,-2), B (2,-1), C (2,0) D (2,1) E (2,2) F(1,2) G (0,2) H (-1,2) I (-2,2) J (-2,1) K(-2,0) L (-2,-1) M (-2,-2) N (-1,-2) O (0,0) P (0,-2) Q (1,-2) Line j = ME Use this figure to complete each statement

5. S:(x,y) -> (-x,-y), S:F -> ____.

6. T:(x,y) -> (x + 2, y-1). T:L -> _____.

7. Ry:J -> ____.

8. Rx:B -> ____.

9. Rj:Q -> ____>

10. Cursive Ro 90:C -> ____.

11. Cursive Ro 180:N -> _____.

12. Ho:K -> ____.

13. Hc:B -> ____.

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