Elitmus
Exam
Numerical Ability
Time Distance and Speed
there is a bridge of 40m length.a cow is standing 5m away from the middle of the bridge.a train is coming from the direction nearest to the cow.if the cow runs towards the opposite direction of the train then he escapes the bridge when the train is 2m away from the bridge and if the cow runs towards the same direction as of the train then the train hits the cow 2m before the other end of the bridge.then what is the ratio of speed of the cow and the train...?
plssss give the solution asked in elitmus 25th may 2014...
options may be: 1:4 4:9 and i dnt remember..
Read Solution (Total 7)
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- 1:5
Let the train be at a distance 'd' from the bridge.
And speed of train be 'x' and speed of cow 'y'
If the cow runs in the opposite direction
(d-2)/x = 15/y
y/x = 15/(d-2) ---(1)
If the cow runs in the same direction of train
(d+38)/x = 23/y
y/x = 23/(d+38) ---(2)
From (1) and (2)
15/(d-2) = 23/(d+38)
d = 77
ie,
Speed of cow/speed of train
= y/x
= 15/(d-2)
=15/75
=1/5
Ratio = 1:5
- 10 years agoHelpfull: Yes(60) No(4)
- 1:5 is right answer...
- 10 years agoHelpfull: Yes(3) No(0)
- 1:4 is right answer
- 10 years agoHelpfull: Yes(2) No(2)
- 1:3
let the ratio be 1:m
x' = dist. of the train from the bridge end
when cow runs towards the train.
(20-5-2)/1 = (x'+2)/m ......(1)
when cow runs away from train
(20+5)/1 = (x'+38)/m .....(2)
=>solving (1)&(2) we get
m=3
- 10 years agoHelpfull: Yes(1) No(6)
- let train y m far away from bridge then the equation-: y-2=4vt
let the bridge length is 2x then then position of cow is=x-5;from the middle point of bridge; x-5=vt
solving it we get y=4x-18.....i
now in 2nd case.....
position of cow is x+3=vt
and position of train=y+2x-2==4vt
solving....it
14+4x=y......ii
now solving iand ii
we get x=16
then 2x=32
- 10 years agoHelpfull: Yes(0) No(1)
- i think 4:3
- 10 years agoHelpfull: Yes(0) No(1)
- Given story is that
2m 5m 2m
hit cow
|.!.......|..!......|.!.........| - 10 years agoHelpfull: Yes(0) No(3)
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