If x, y, and z are consecutive negative integers, and if x > y > z, which of the following must be a positive odd integer?

A)xyz

B)(x - y) (y - z)

C)x - yz

D)x(y + z)

E)x + y + z

• (x - y) (y - z) will be positive odd integer
• 13 years agoHelpfull: Yes(18) No(3)
• both b and e
  let x=-1 y=-2 z=-3
  (x-y)(y-z)=(-1+2)(-2+3)=1
  x(y+z)=-1(-2+(-3))=-1(-5)=5
  so in both cases we get positive odd integer
• 10 years agoHelpfull: Yes(5) No(2)
• d)x(y+z)because x is negative and (y+z) becomes -ve so - and - becomes +ve
• 10 years agoHelpfull: Yes(4) No(3)
• Let Consecutive negative integers=-1,-2,-3(two odd and one even) or -2,-3,-4(two even and one odd)
  option(A) XYZ is always negative only so no need to substite.
  option(B) is the answer....substitute the values.....u will get the positive odd integer.
  
• 10 years agoHelpfull: Yes(0) No(0)
• take for example -1,-2,-3 then (-1+2)*(-2+3) =1 i.e. positive odd integer so B) is correct
• 8 years agoHelpfull: Yes(0) No(0)