find the maximum value of n such that 77! is per fectly divisible by 720^n

• 720 -> 2^4 * 3^2 * 5^1
  To find the max. power of 720, it is enough to find the maximum power of "5"... Since 5 is the largest prime factor here...
  77/5^1 + 77/5^2 + 77/5^3 = 15+2+0 = 17 [Quotient only]
  Max. power of 5 is 17... Hence max. power of 720 is "17"...
  
  Ans : 17
• 10 years agoHelpfull: Yes(6) No(2)
• 77/5=15
  15/5=3
  so no of 5 is the maximum power of n
  no of 5 =15+3;
  =18 Ans
• 10 years agoHelpfull: Yes(2) No(0)