in how many ways can the letters of the word college be arranged.such that its vowels do not come to gether

• Total no.of words COLLEGE can be arranged in 7!/2!*2!=1260
  Vowels OEE come together=CLLG(OEE)=5!/2!*3!/2!=60*3=180
  Vowels do not come together=1260-180=1080
• 10 years agoHelpfull: Yes(34) No(3)
• college=7!/2!*2!=1260
  5!/2!*3!/2!=180
  1260-180=1080
  
• 10 years agoHelpfull: Yes(8) No(0)
• COLLEGE is a 7 letter word.
  here E and L will appears two times so we will get in denominator (2!*2!)
  COLLEGE can be arranged in 7!/(1!*1!*2!*2!*1!)=1260
  It is difficult to calculate Vowels don't come together now we are going to calculate vowels come together.
  CLLG(OEE) =4+1 consider OEE as one letteer.
  then vowels come together =(5!/2!)*(3!/2!)=180 (3!/2! is the arrangement of vowels total 3 vowels 3! and E repeats two times.)
  vowels don't come together =1260-180=1080.
  
• 8 years agoHelpfull: Yes(6) No(0)
• The ans should be 1080.
  It can be calculated as:
  Total possible combinations from word College = 7!/(2!*2!)=1260
  Combinations in which vowels appear together = (5!/2!)*(3!/2!)=180
  So combinations in which vowels don't appear together = 1260 - 180 = 1080
  
• 10 years agoHelpfull: Yes(5) No(1)
• 1080 IS THE ANS
• 8 years agoHelpfull: Yes(1) No(1)
• 7!/2!*2!=1260
  5!/2!*3!/2!=180
  1260-180=1080
• 8 years agoHelpfull: Yes(1) No(0)
• COLLEGE:-
  we will arrange this one in:-
  7!/2!*2!=1260.
  1) vowels come together:- (o,e,e)
  we arrange (o,e,e) in 3!/2! ways.
  and we take (o,e,e) as 1 word. and now total we have 5!/2!*2!.
  now we will multiply
  3!/2!*2! * 5!/2!*2!=90.
  2) vowels do not come together:-
  1260-90 = 1170.
• 8 years agoHelpfull: Yes(1) No(4)
• Here you are considering only the words where the vowels o,e,e together. But we have to consider those words also where only 2 of the 3 vowels are together.
  So, here we are taking 4 consonants.
  c,l,l,g.
  These are to be written like _c_l_l_g_
  These 4 consonants can be selected in 4!/2! ways.
  Then 3 vowels can be places in 5 positions in 5P3/2! ways
  So the no. of words where vowels are together is=4!/2! * 5P3/2! =360
  so the no of words where vowels are not together=1260-360 =900
• 8 years agoHelpfull: Yes(0) No(5)
• college can be formed in 7!/2!*2!=1260
  Vowels OEE come together=CLLG(OEE)=5!/2!*3!/2!=60*3=180
  remaining 1260-180=1080
• 8 years agoHelpfull: Yes(0) No(0)
• 4p3*4p3*2
  =1152
• 8 years agoHelpfull: Yes(0) No(0)