A rectangular park, 70m * 30m has two roads which are 5m wide one parallel to its length and the other to its breadth. How much will it costs to gravel the roads at rs 4 per sq.m?
Option
A) RS 475
B) RS 1,900
C) RS 950
D) RS 1,425

• B) Rs. 1900
  
  Area of road parallel to the length= 70*5=350 sq.m.
  Area of road parallel to the breadth=30*5=150 sq.m.
  Total area of road=350+150=500 sq.m.
  As these two road contains common area of 5*5=25 sq.m., so subtract once this common area, so actual area of road=500-25=475
  Cost to gravel @ 4 Rs./sq.m.= 475*4=1900 Rs.
• 10 years agoHelpfull: Yes(50) No(0)
• Parallel road on both side
  so the new rectangular park 65m * 25m
  
  =(70m * 30m) - (65m * 25m)
  =2100-1625
  475sq.m.
  
  =475 * 4
  =1900 Rs
• 10 years agoHelpfull: Yes(13) No(0)
• answer is 'b'.
  area of crossroad is= (70*5)+(50*5)-5*5=475 m^2
  cost of gravelling is 475*4= Rs 1900/-
  
• 10 years agoHelpfull: Yes(2) No(0)
• Using BODMAS rule, its 23/21
  
• 9 years agoHelpfull: Yes(0) No(7)
• Area of a rectangle = L*B,
  Area of road parallel to its length=70*5 =350,
  Area of road parallel to its length=30*5 =150,
  Total area=350+150 =500 sq.mt
  These two roads contain a common area= 5*5= 25 sq.mtr
  Subtract these this common area= 500-25 =475,
  
  Cost to gravel=4*475 =Rs 1900
• 9 years agoHelpfull: Yes(0) No(0)