A vessel is filled with liquid , 3 parts of which are water and 5 parts symp. How much of mixtuer must be drawn off and replace with water So that the mixture may be half water and half symp.

• one fifth of total volume should be taken out and filled with same amt of water to get mixture of half water and half symp.
  For example
  If initial mix is 40 kg with 15 kg water and 25 kg symp.
  Take out 8 kg of mixture having 3 kg of water and 5 kg of symp.
  left out 12 kg water and 20 kg symp.
  adding 8 kg of water will make mixture of 20 kg water and 20 kg symp.
• 10 years agoHelpfull: Yes(2) No(0)
• consider it initially contains 8 litres of liquid
  let x litres of this liquid be replaced with water
  quantity of water in new mixture is=3-3x/8+x
  quantity of syrup in new mixture is= 5-5x/8
  3-3x/5-5x/8-> x=8/5 so part of mixture replaced is 8/5*1/5=1/5
  
• 10 years agoHelpfull: Yes(1) No(0)
• x = total amt of liq.
  3/8* x = pure water
  5/8 * x = pure symp
  ==================
  y part will be drawn
  therefore
  3/8(x-y) = pure water
  5/8(x-y) = pure symp
  so
  =====================
  3/8(x-y) + y = x/2 (y amt of water is added after the drawn of y amt of mixture)
  y = x/5
  ================
  so 1/5 th
• 10 years agoHelpfull: Yes(1) No(0)