If there is a cube of dimension 7*7*7 which is made up of 343 smaller cube. A square of dimension 3*3*3 is inserted on each face of the cube. what is the total number of replaced smaller cube? A) 109 B) 162 C) 192 D) ?

• I guess 162
  dimension of each smaller cube is 1*1*1, since 7*7*7=343 & it is made of 343 smaller cube so dimension of any smaller cube is 1-1-1.
  now 3*3*3=27, therefore 27 smaller 1-1-1 cube has to be replace from each face
  since we have total 6 faces, therefore 27*6=162
• 10 years agoHelpfull: Yes(24) No(4)
• How can there be a square of dimension 3*3*3
• 10 years agoHelpfull: Yes(4) No(1)
• 134
  27+27 from two opposite faces.
  21+21 from next two opposite faces.
  19+19 from the remaining opposite fACES
• 10 years agoHelpfull: Yes(4) No(0)
• 162
  
  3*3*3=27, therefore 27 smaller cube 1*1*1
  so. 6*27 = 162.
• 10 years agoHelpfull: Yes(3) No(0)
• how come there can be 8 cubes of 3*3*3 dimension, deepak kumar
• 10 years agoHelpfull: Yes(2) No(0)
• I think 216
  7*7*7=343,hece smaller cube dimensions is 1*1*1
  total 8 cube are inserted of dimesions 3*3*3
  hece total replace cube is 27*8=216
• 10 years agoHelpfull: Yes(1) No(6)
• I think There is something wrong with the question because if we have inserted two 3*3*3 cubes on opposite faces of 7*7*7 cube how can we place another 3*3*3 on other faces as the 3*3*3 cube replaced earlier will resist them.
• 8 years agoHelpfull: Yes(0) No(0)