Let c who can crack dis
5 - 4 = 23
8 - 1 = 63
6 -16 = 32
9 - 9 = 78
3 - 9 = 6
3 - 81 = ?
Genius heads try this

• 0
  
  5^2-Sqrt(4)=23
  8^2-Sqrt(1)=63
  6^2-Sqrt(16)=32
  .
  .
  3^2-Sqrt(81)=0
• 10 years agoHelpfull: Yes(8) No(3)
• sqr(3)-sqrt(81)=9-9=0
• 10 years agoHelpfull: Yes(4) No(3)
• Squaring first term - square root of last term = Given term is the solution
  eg: for 6-16=32
  6^2=36
  sqrt(16)=4
  so 36-4=32
• 10 years agoHelpfull: Yes(1) No(0)
• 0
  
  Square of no-Square Root of no=...
  25-2=23
  64-1=63
  36-4=32
  81-3=78
  9-3=6
  9-9=0 will be the ans
• 10 years agoHelpfull: Yes(0) No(0)
• 3 - 81 = 0
• 9 years agoHelpfull: Yes(0) No(0)
• Answer is 0
  expalnation :
  (5^2)-(sqrt of 4)=25-2 =23
  (8^2)-(sqrt 0f 1)=64-1 = 63
  (6^2)-(srqt of 16)=36-4=32
  (9^2)-(sqrt of 9)=81-3 =78
  (3^2)-(sqrt of 9) = 9-3=3
  for
  (3^2)-(sqrt of 81) = 9-9 =0
  
  So, the answer will be 0
• 8 years agoHelpfull: Yes(0) No(0)
• 0
  
  because 9-9=0
• 8 years agoHelpfull: Yes(0) No(0)
• 25-2(4=2^2)=23
  64-1=63
  36-4=32
  81-3=78
  9-3=6
  9-9=0
• 7 years agoHelpfull: Yes(0) No(0)