given that ((2)^2)^5+1=p*q,where p and q are two positive integer number.what are the value of p and q

• ((2)^2)^5*((2)^2)^1=p*q
  (4)^5*(4)^1=p*q
  1024*4=p*q
  p=1024
  q=4
• 10 years agoHelpfull: Yes(0) No(1)
• ((2)^2)^5+1= 1025= 205*5 (Precedence rule)
  p = 205
  q = 5
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• ((2)^2)^5+1= 1025= 205*5
  p = 205
  q = 5
  or
  p=5
  q=205
• 10 years agoHelpfull: Yes(0) No(0)