From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?

A. 564 B. 645
C. 735 D. 756

• we have 3m and 2w
  or
  4m and 1w
  or
  5m
  no of ways =(7C3 x 6C2) + (7C4 x 6C1) + (7C5)= = (525 + 210 + 21)
  = 756.
  
• 13 years agoHelpfull: Yes(14) No(0)
• We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).
  
  Required number of ways = (7C3 x 6C2) + (7C4 x 6C1) + (7C5) = = 525 + 210 + 21 = 756
  
  so 756
• 13 years agoHelpfull: Yes(7) No(0)
• either 3 men & 2women OR 4 men & 1 woman OR 5 men
  required no of ways =(7C3 x 6C2) + (7C4 x 6C1) + (7C5)
  = 525+210+2
  = 756
• 13 years agoHelpfull: Yes(4) No(0)
• Answer is C. (7c3*6c2) + (7c3*4c2)
• 13 years agoHelpfull: Yes(0) No(6)
• We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).
  Required number of ways = (7C3 x 6C2) + (7C4 x 6C1) + (7C5)
  =756
  
  
• 9 years agoHelpfull: Yes(0) No(0)