How many 5 digit no. can b formed wit digits 1, 2, 3,4,5,6 which r divisible by 4 and digits not repeated.
please tell steps

• 192
  
  last 2 digits are 12,16,24,32,36,52,56,64 = 8 ways
  
  reamining 3 digits in 4*3*2 ways
  
  total = 4**3*2*8 = 192 ways
• 14 years agoHelpfull: Yes(19) No(6)
• Well here is the solution:-Take 5 blanks _ _ _ _ _.
  Since the number has to be divisible by 4 we can have only the following cases
  12,16,24,32,36,52,56,64.That is you can fill the last two blanks in eight ways.
  Now take the first three blanks.Since we already selected 2 numbers,we are left with 4 numbers.
  That is we can fill the first blank in 4 ways,similarly the second in 3,the third in 2 ways.
  By fundamental principle of counting we have to multiply all of them.
  That is 4 x 3 x 2 x 8=192.
• 8 years agoHelpfull: Yes(2) No(1)