how+much=power then p+o+w+e+r=?

• --How --> 3-digit value
  +Much --> 4-digit value
  Power --> 5-digit value
  *********************************
  w+h=r, o+c=e, h+u=w, _+m=o,
  
  Note here "m" is added with no alphabet... So if i take "M" value between (0-8), it ll not produce a remainder... So it ll again produce a 4-digit no.... But our final result should be a 5-digit value...
  If 3-digit + 4-digit = 5-digit means, 1st no. of 4-digit no. should start with "9"...Nd obviously the 1st no. of 5-digit ll be "1" nd 2nd no. ll be "0"...
  So here P=1...M=9... O=0...
  So Definitely P=1, m=9, O=0
  
  So remaining numbers we can use is {2,3,4,5,6,7,8}
  So Take "R=2" first...
  Possible values of (W,H) ll be (4,8), (5,7), (7,5) (8,4)
  When v take (W,H) = (4,8) , we cannot get (H+U) =w...
  So take (W,H) = (5,7)... So W=5, H=7, R=2 carry 1...
  Already O=0... So possible value of C ={3,4,6,8}...
  When C=3, C={carry+0+3}=4... So E=4...
  H is already 7... Possible values of U={6,8}...
  We need to get H+U=W... (ie) Result should be 5... So U should be 8... 7+8=5 carry 1...
  M is already 9... So {carry + 9} = 0 carry 1...
  nd hence P=1 (carry of prev result)
  
  HOW ==> 705
  MUCH ==> 9837
  POWER ==> 10542
  
  705
  (+)9837
  -------------------
  10542
  ------------------
  P+O+W+E+R = 1+0+5+4+2 = 12
  
  Ans : 12
  
• 10 years agoHelpfull: Yes(32) No(1)
• @SARASWATHY can u please give some materials on this type problms..and please provides some links..
• 10 years agoHelpfull: Yes(1) No(0)
• 803
  9468
  ------------
  10371
  .....first three digit can be obtained by the concept described by sarshwathy...and remaining can be done by selecting proper digits...though the addition me produce differ result ...but p+o+w+e+r...well always be 12
• 10 years agoHelpfull: Yes(0) No(1)
• ans is 12 :)
• 10 years agoHelpfull: Yes(0) No(0)
• H O W
  7 0 5
  M U C H
  + 9 8 3 7
  ______________
  P O W E R
  1 0 5 4 2
  
  THEN P+O+W+E+R=1+0+5+4+2=12
• 10 years agoHelpfull: Yes(0) No(0)
• HOW ==> 805
  MUCH ==> 9718
  POWER ==> 10523
  
  705
  (+)9837
  -------------------
  10542
  ------------------
  P+O+W+E+R = 1+0+5+2+3 = 11
  
• 10 years agoHelpfull: Yes(0) No(0)
• how + much = POWER.
  p=1,
  o=0,
  m=9 obvious.
  now. if w= 5, h=7, so it gives exact answer. 10542
• 8 years agoHelpfull: Yes(0) No(0)
• ·····h·o·w
  +·m·u·c·h
  --------------
  p··o·w·e·r
  
  Since there are no numbers above the p, it must be a 1. Since
  there is only one number above the m, it must be a 9 and o must be a 0. So, so far we have
  p = 1, o = 0, m = 9
  
  For the o + c = m column to work out, w+h must be greater than 9 so that a 1 gets carried into the next column. So it must be true that
  1+c = e.
  
  It must also be true that
  h + u = 10 + w and
  w + h = 10 + r
  
  So 2h + u = 10 + w + h = 20 + r.
  That is u - r = 20 - 2h
  
  If h=8, then u-r = 4
  If h=7, then u-r = 6
  If h=6, then u-r = 8
  
  There are no other possibilities.
  
  So the following combinations are possible for o,p,r,h,u,and m.
  
  0·1·2·3·4·5·6·7·8·9
  o·p·r ···w···u···h·m
  o·p····r ···w··u·h·m
  o·p·r·······w· h·u·m
  
  Since e = c+1, we need room
  for e followed by c. The only
  possibility from the above is
  
  0123456789
  oprcew·hum
  
  So
  
  how
  much
  -----
  power
  
  becomes
  
  705
  9837
  -----
  10542
  
  p+o+w+e+r = 12
• 6 years agoHelpfull: Yes(0) No(0)