raju can do a piece of work in 10 days.vickey in 12 days and tinku in 15 days.they all work together but raju leaves after 2 days and vicky leaves 3 days before the work is completed. in how many days is the work is completed.

• 7 days......Let the work be completed in x days. Then according to question
  2/10 +(x-3)/12 + x/15 =1 or, (12+5x-15+4x)/60=1 or, 9x-3=60 or, x=63/9=7 hence whole work completed in 7 days
• 10 years agoHelpfull: Yes(1) No(0)
• 7days..
  work done in 2 days = 20% + 17 5 % + 13.33 = 50.33%
  in last 3 days only tinku works so work completed in last 3 days=20%
  so work done by vicky nd tinku together = 100-50.33-20= 29.67%
  work comleted by vicky nd tinku together in a day= 8.5+6.66=15.165
  so vicky nd tinku must be work together 2 days
  so total days = 2+2+3=7days
• 10 years agoHelpfull: Yes(0) No(0)
• 7 days
  
  2 days work of Raju+Vicky+Tinku=2[(1/10)+(1/12)+(1/15)]=1/2
  After 2 days if only Tinku works for 'x' days, then Vicky works for (x-3) days
  So (1/2)+(x-3)(1/12)+x(1/15)= 1 ,on solving, x=5
  Total days to complete the work=2+5=7
• 10 years agoHelpfull: Yes(0) No(0)