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At what rate of simple interest per annum an amount will be doubled in 10 years?
Read Solution (Total 8)
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- actual amount=p
now it is doubled amount=2p
S.I=2p-p=p
S.I=ptr/100
r=SI*100/pt=p*100/p*10=10
r=10% - 10 years agoHelpfull: Yes(16) No(0)
- 10%
If Principal=p, Rate%=r
For amount to double in 10 years, (p*r*10)/100 =p, r=10 - 10 years agoHelpfull: Yes(6) No(5)
- let the sum be 100, time=10, rate=R.
given that the amount is doubled after 10 years which implies that
S.I= (P*R*T)/100
=> 200=(100*R*10)/100
=> R=20% - 10 years agoHelpfull: Yes(6) No(16)
- 10%.
rate = ( interest*100)/(principal *time) =(x*100)/(x*10)=10 % - 10 years agoHelpfull: Yes(4) No(3)
- Let principal amount be rs x.
amount=rs 2x
simple interest=2x-x=rs x
x=(x*10*rate)/100
rate=100/10=10% - 10 years agoHelpfull: Yes(2) No(0)
- 2x=(x*R*10)/100
which gives R=20
SO RATE BE 20% - 10 years agoHelpfull: Yes(0) No(2)
- S.I=p*r*t/100
let principal be rs.100 since amount doubles in 10 yrs amount will be rs.200 ,but S.I is rs 100
so,100=100*r*10/100 and ans is 10% - 10 years agoHelpfull: Yes(0) No(0)
- 10%,100=100*r*10/100=>r=10
- 10 years agoHelpfull: Yes(0) No(0)
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