A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?

A. Rs. 1090 B. Rs. 1160
C. Rs. 1190 D. Rs. 1202

• answer=1190
  since,c.p=1400
  loss%=(c.p-s.p)/c.p*100
  15=(1400-s.p)/1400*100
  so,after solving answer=1190.
  
• 10 years agoHelpfull: Yes(15) No(0)
• 15% of 1400 is 210
  so,1400-210=1190
  ans isC
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• 1400*85/100=1190
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• s.p=100-loss%/100*c.p
  s.p=100-15/100*1400
  s.p=85*14=1190
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• S.P.=(100-LOSS%)*(C.P./100) so
  S.P.=(100-15)*?(1400/100)=1190
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• 1400*.85=1190
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• Loss=1400*15/100
  =210
  selling price=1400-210
  =1190
  
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• 1400*15/100=210 LOSS IN SELLING
  1400-210=1190
  ANSWER C
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• for 100 1400
  since 15% loss
  for 85 how much?
  so s.p=(85*1400)%100=1190
  
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• Ans:1190
  Selling Price: (S.P.)
  SP =(100 - Loss %)/100 x C.P.
  =(85/100)x1400
  =1190
  
  
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• 1400*(85/100)=1190
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• 1400*15/100=210=loss
  sp=1400-210=1190
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• sp= 100-15/100*1400
  85*14
  1190 ans
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• @dipankar Kumr: which formula you have used?
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• 1190, Loss= 210
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• c.!!90 using formula 100-loss/100*c.p
  
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• C.1190...1400-(15/100)*1400
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• buying price=1400
  15% of 1400=210
  => selling price = 1400-210=1190
  So, answer is C.Rs. 1190
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• answer c
  c.p=1400
  loss=15% of 1400=210
  selling price=1400-240=1190
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• ANS WILL BE (C)...1400-(1400*0.15)=1190
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• ans c)1190
  loss%=(cp-sp)/cp*100
  ans=1190
  
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• 1190
  15% of 1400 is 210
  so,1400-210=1190
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• 1190 becoz selling price is 85% of 1400..which is 1190
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• cost price=rs.1400
  loss=15%
  sell price=cost price(1-loss/100)
  =1400(1-(15/100))=(1400*85)/100=rs.1190
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• ans:C
  100% value is given as 1400
  85% value i.e (100-15)% is (14*85)=1190
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• 1190
  1400*15/100=210
  1400-210=1190
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• 1190..apply simple loss % formula. Direct SUbstitution.
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• SP=(100-LOSS%)/100*CP
  So SP=(100-15)/100*1400
  SP=1190
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• C, Loss=Rs. 1400*15/100=210
  SP=CP-Loss=Rs1190
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• 1190 is the right answer
  (85/100)*1400=1190
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• Answer:c.Rs.1190
  cost price=1400Rs
  loss %=15%
  selling price=15/100*1400
  =210
  subracting the loss % from the original price
  selling price=1400-210=1190
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• S.P=((100-LOSS%)/100)*C.P
  
  S.P=1190
  C.P=1400
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• answer is(c)
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• sp=(100-15/100)*1400
  sp=1190
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• (1400*15)/100=210
  1400-210=1190
  ans- c
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• ans is: 1190
  
  given that: CP=1400
  loss% = 15%
  SP= ?
  
  SP=[(100-loss%)/100]*CP
  =[(100-15)/100]*1400
  = (85/100)*1400
  = 85*14
  = 1190
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• 85 percent of 1400=1190
  
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• since for 1kg there is a loss of 100gm (10%)
  that meanfor 10kg there will be a loss of rs 27
  for 1kg there will be a loss of rs 2.7
  if selling price is rs 27/kg
  and there is neither profit no loss
  the actual cp= 27-2.7=rs 24.3
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• c
  Rs 1190
  
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• Ans is 1190
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• 1190, 15=(1400-sp)*100/1400=>sp=1190
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• cp=1400
  loss=15%
  sp=(85/100)*1400
  ==1190rs
  
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• 1190
  C.P.=1400
  15% of cp=loss=210
  S.P.=C.P.-loss=1190
  
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• CP=1400
  LOSS=15%
  SP=1400-((15/100)*1400)=1190
  
  
  
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• sp=cp*loss%
  1400*85/100
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• answer is C(1190)
  sp=(100-loss)%*cp/100
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• formula s.p=((100-loss%)/100)*c.p
  1190 ans.
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• 1190ans
  15%*1400=210
  1400-210=1190
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• buying at cost is 1400/-
  selling it lose is 15% ie (15/100)*1400= 210;
  therefore 1400-210=1190
  
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• loss=15%=0.15
  factor=1-0.15=0.85
  s.p=F*c.p=1400*0.85=1190
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• cost price=1400
  loss=15%
  he get 100-15=85% on cost price
  then 85%of 1400 is
  (85/100)*1400=85*14=1190
  hence solution is Rs. 1190
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• s.p= (85/100)*1400 =1190
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• ans-1190
  loss=15% of 1400=210
  sp=1400-210=1190
  
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• 1190
  85/100*1400
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• c
  sp= (100-loss%)/100+cp
  
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• the cost price is given to us that is 1400 and 15% loss means 210,
  thus total loss on c.p.of cycle is 1190 that will be its selling price
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• s.p=((100-loss)*c.p)/100
  85*1400/100=1190
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• 1190
  
  but this is not ths TCS level . sp dont make fool
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• Given C.P=1400
  S.P=((100-loss%)/100)*C.P
  S.P=1190.
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• (85/100)*1400=1190
• 7 years agoHelpfull: Yes(0) No(0)