which term of the A.P.3,15,27,39.....is 132 more than its 54th term.

• 65th
  
  Given, a=3,d=12
  54th term=3+(53)12=639
  132+639=771
  The 'n'th term which is 771, 3+(n-1)12=771, n=65
• 10 years agoHelpfull: Yes(2) No(0)
• The common difference is d=12
  so 132/12=11
  54+11=65th term
• 10 years agoHelpfull: Yes(2) No(0)
• 65th term
  54th term = 3 + (54-1)*12 = 639
  let,
  Tn term of A.p. is 132 more than 54th term
  then,
  Tn = 132 + 54th term
  Tn = 132 + 639 = 771
  3 + ( n - 1 )*12 = 771
  n = { (771 - 3) / 12 } + 1
  n = 65
  answer : 65th term
• 10 years agoHelpfull: Yes(1) No(0)