In a horse race, the horse A's chances of winning are 1/6, the horse B's chances are 1/10 and those of the horse c are 1/8. If the race starts with twelve horses and only one horse wins, then what are the chances that one of these three horses will win?
(a)57/120 (b) 47/120 (c) 37/120 (d) 27/120

• P(A)=1/6
  P(B)=1/10
  P(C)=1/8
  Probability that one of these three horses will win is given by
  P(A)OR P(B)OR P(C)= (1/6)+(1/10)+(1/8)= 47/120
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• simply add all three probability
  1/6 +1/8 + 1/10 = 47/120
  option b
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