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Maths Puzzle
Numerical Ability
Sequence and Series
6, 12, 21, ?, 48
A. 33 B. 38
C. 40 D. 45
Read Solution (Total 9)
-
- 6, 12, 21, x, 48
--6----9---12---15--
x = 21+12 = 33
Ans : A) 33
- 10 years agoHelpfull: Yes(9) No(0)
- The ans is a.33
The difference between the terms is a multiple of 3
i.e.6,9,12,15
6+6=12
12+9=21
21+12=33
33+15=48 - 10 years agoHelpfull: Yes(1) No(0)
- A. 33
12-6=6
21-12=9
x-21=12(assumed to be) as 6,9,12,15 are forming an AP with d=3
48-x=15
x=21+12 or we can say 48-15=33 - 10 years agoHelpfull: Yes(0) No(0)
- A)33
12-6=6 21-12=9 x-21=12 48-x=15
x=21+12 = 33 or 48-15=33
ans- 33 - 10 years agoHelpfull: Yes(0) No(0)
- Answer is 33
Sequence is increasing by 6 ,9,12,15 - 10 years agoHelpfull: Yes(0) No(0)
- A=33
6+6=12
12+9=21
21+12=33
33+15=48.. - 10 years agoHelpfull: Yes(0) No(0)
- ans-a
the diff btn two num given in the question are the multiples of 3
btn 6 and 12 diff is 6
btn 12 and 21 diff is 9
similarly diff btn 21 and ? may be 12
and diff btn ? and 48 may be 15 the num which satisfies above conditions is 33 - 10 years agoHelpfull: Yes(0) No(0)
- in this we add 6 9 12 15 18....respectively.
6+6=12
12+9=21
21+12=33
33+15=48 - 10 years agoHelpfull: Yes(0) No(0)
- 33, the different bt no. Is increasing in order of 6,9,12,15,
- 10 years agoHelpfull: Yes(0) No(0)
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