(10!+111)/143 what is the remainder??

• 143 => 11*13
  
  10! mod 11 + 111 mod 11 = R1
  R[(p-1)!/p] = p-1 [Provided p is a prime no.]... So R[10!/11] = 10...
  10 + 1 mos 11 => 11 mod 11 = 0
  R1 = 0
  
  10! mod 13 + 111 mod 13 = R2
  6 + 7 mod 13
  13 mod 13 = 0
  R2 = 0
  
  Rem = 11x+R1 = 13y+R2
  Rem = 11x+0 = 13y+0
  x = 13, y = 11
  143 mod 143 = 0
  
  Ans : 0
• 10 years agoHelpfull: Yes(9) No(0)
• 10!=3628800 10!+111=3628911/143=25377
• 10 years agoHelpfull: Yes(0) No(2)