if P(A)= 1/3 ,P(B)=1/2 ,P(A INTERSECTION B)= 1/4 , then find P(A' U B')?

• P(A') = 1-1/3 => 2/3
  P(B') = 1-1/2 => 1/2
  P(A' n B') = 1-1/4 => 3/4
  P(A' U B') = P(A')+P(B')-P(A' n B')
  => 2/3+1/2 - 3/4
  => 8+6-9/12
  5/12
  
  Ans : 5/12
• 10 years agoHelpfull: Yes(8) No(3)
• P(A' U B' ) = 1 - P(A INTERSECTION B)
  = 1 - 1/4
  = 3/4
• 10 years agoHelpfull: Yes(5) No(1)
• @vibha
  
  its P(A' U B') not P(A U B)
• 10 years agoHelpfull: Yes(1) No(0)
• p(A U B) = p(A) + p(B) - p(A INTERSECTION B )
  = 1/3 + 1/2 -1/4
  = 7/12
• 10 years agoHelpfull: Yes(0) No(4)
• @saraswathy
  thanks for correcting me
• 10 years agoHelpfull: Yes(0) No(0)
• @saraswathy
  3rd line it should be
  P(A n B)' = 1 - P(A n B)
  WHICH IS NOTHING BUT P(A' U B')
• 10 years agoHelpfull: Yes(0) No(0)
• P(A'UB')= 1 - P(A n B)
  so answer is 1-1/4=3/4
• 7 years agoHelpfull: Yes(0) No(0)