In an examination,a student gets 5 marks for every right answer and loses 2 marks for every wrong answer.If he answers 50 questions and get 124 marks, how many are correct answers he attempted?

• Let us assume he answered 'r' right answers and 'w' wrong answers.Then acc.. to given question, the equations would be,
  5r-2w = 124 // as for right answer 5 mrks and wrng answer -2 mrk
  r+w = 50 // total attempted questions
  solving above eqns,we get r = 32
  32 are correct answers
• 10 years agoHelpfull: Yes(6) No(1)
• let noof correct ans as x and wrong answers as y.
  x+y=50 (total noof qstns answered)
  5x-2y=124
  
  by solving above two qstns we get x=32,y=18
  he attempted 32 correct answers
• 10 years agoHelpfull: Yes(0) No(0)
• let number of correct question done=x,therefore,no.of wrong questions done=50-x,according to question,total mark=124,i.e 5x-2(50-x)=124
  =>x=32
• 10 years agoHelpfull: Yes(0) No(0)
• wrong answer=y
  correct answer=x
  total x+y=50;
  now he wrote some questions correct and some of wrong he get 124 marks
  so 5x-2y=124
  solve 2 eqns then we get x=32
  
• 10 years agoHelpfull: Yes(0) No(0)
• 25 ans he attempt corrct
• 9 years agoHelpfull: Yes(0) No(0)
• lets x correct answer and 50-x wrong answer then
  x*5-(50-x)*2=124
  5x-100+2x=124
  7x=224
  x=32
  
• 9 years agoHelpfull: Yes(0) No(0)
• let x = no. of the correct answer and y= no. of incorrect answer
  then x+y=50 => x=50-y
  for each right answer, the student gets 5 marks, and for the wrong answer loses 2 marks.
  => 5x-2y=124
  by putting x=50-y
  =>5(50-y)-2y=124
  250-5y-2y=124
  -7y=124-250
  -7y=-126
  y=126/7
  y=18
  now putting y=18 on x=50-y
  =>x=32
  => The student attempted 32 questions correct
• 3 years agoHelpfull: Yes(0) No(0)