How many 7 digit numbers are there having the digit 3 three times and the digit 5 four times a

it will be 7!/3!x 4!, since 3 is occuring 3 times and 5 is occuring 4 times.
Which is 35.
So ans is 35
10 years agoHelpfull: Yes(65) No(1)

for digit 3 it will be 7!/3!
as it can be placed at all the seven positions.
Now for 5 it will be 4! as it can be placed in 4 places
so ans is 7!/3!*4!
10 years agoHelpfull: Yes(9) No(2)
d
ans is 35
10 years agoHelpfull: Yes(4) No(1)
d) 35
from 7 digit there are 7! number,
but 3,4 are repeating
total numbers are 7!/3!*4!=35
10 years agoHelpfull: Yes(2) No(1)
33355555
7!/(3!*5!)
10 years agoHelpfull: Yes(1) No(17)
There are basically 7 places so using permutation formula for arrangment
7!/3!*4!
since 3! because (7-4)!
and 4! because(7-3)!
10 years agoHelpfull: Yes(1) No(0)
35WILLBE THE ANS BECAUSEWECAN CHOSE 3PLACES AMONG=7C3 WAYS
and then arrange 5 in remaining places hence=7c3/4!*3!=35ans
10 years agoHelpfull: Yes(0) No(1)
Here 7!/(3! * 5!)

Finally u got ans is 35
10 years agoHelpfull: Yes(0) No(2)
3335555 so and will be 7!/3!4!= 35
10 years agoHelpfull: Yes(0) No(0)
option a) is correct
9 years agoHelpfull: Yes(0) No(0)

How many 7 digit numbers are there having the digit 3 three times and the digit 5 four times?

a) 7!/(3!)(5!)

b)3^3*5^3

c)7^7

d)35