How many small cuboids of dimension 2m X 3m x 4 m can be accommodated in a cube of side 22 m?

• 2*3*4=24
  22^3=10648
  then 10648/24=443
• 10 years agoHelpfull: Yes(28) No(31)
• I guss 385
  
  take one side first
  22 for large and 4 for small (4 is 1st larger side)
  22/4=5.5 => 5
  take next side first
  22 for large and 3 for small (3 is 2nd larger side)
  22/3=7.333 => 7
  take next side first
  22 for large and 2 for small
  22/2=11
  So 5*7*11= 385
• 10 years agoHelpfull: Yes(23) No(8)
• no of cuboids= surface area of cube / surface area of cuboid
  = ( 6a^2 ) / ( 2(lb+bh+lh) )
  = ( 6*22*22 ) / ( 2(2*3+3*4+2*4))
  = 726 / 13
  = 55 cuboids
• 9 years agoHelpfull: Yes(6) No(9)
• it might be 385
  coz the question is how many small cuboids with 2*3*4 with the cube's side of 22m
  then
  for taking sides differently
  we may get 11,7,5
  totally 11*7*5 =385
• 9 years agoHelpfull: Yes(5) No(8)
• 385 small cuboids can be accommodated.The cube cannot hold half a cuboid so dimensions will have remainders 0*1*2 respectively.Now volume of accommodated cube is 22*21*20 and no. of cuboids=22*21*20/(2*3*4)=385
• 9 years agoHelpfull: Yes(3) No(2)
• I think 420
• 8 years agoHelpfull: Yes(3) No(4)
• Arrange the cuboids along the 2m sides on an edge of the 22 m cube.
  Total cuboida in a row = 22/2=11
  No. of cuboids along the 3m edge = 22/3 ~= 7
  No. of cuboids along the height of the cube = 22/4 ~= 5
  So, total no. of cuboids = 11*7*5 = 385
• 7 years agoHelpfull: Yes(2) No(0)
• The 2 digit Number is 81.
  Here lets give a bottom up approach to proceed easily.
  the 2 digit perfect square numbers are 16,25,36,49,64,and 81.
  Lets proceed from the larger number 81-> sum of the digits=9
  81/9=9(SQRT of 81)...
  Hence the 2 digit is 81..
• 9 years agoHelpfull: Yes(1) No(5)
• can any one give a proper solution to it?
• 8 years agoHelpfull: Yes(1) No(1)
• ans is 420
• 8 years agoHelpfull: Yes(1) No(1)
• 443 cuboids. cube volume=22^3 ; cuboid volume = 2*3*4=24;
  no of cubboids accomodated in this cube = 10648/24 = 443.67= 443 cuboids.
• 7 years agoHelpfull: Yes(1) No(1)
• 1.Arrange the cuboids along the 2m sides on an edge of the 22 m cube.
  Total cuboida in a row = 22/2 = 11
  2.No. of cuboids along the 3m edge = 22/3 ~= 7
  3.No. of cuboids along the height of the cube = 22/4 ~= 5
  So, total no. of cuboids = 11*7*5 = 385
  NOTE:You can't go by volume as it is a cuboid not a cube.
• 7 years agoHelpfull: Yes(1) No(0)
• No.of cuboids= volume of cube/ volume of cuboid
  = (22*22*22)/(2*3*4)
  =10648/24
  =443 cuboids.
• 7 years agoHelpfull: Yes(1) No(1)
• I guess the question is given wrong.,....:)
• 8 years agoHelpfull: Yes(0) No(4)
• for free apps classes plz contact DR.ELANGO 9551026952, elangocruzer@hotmail.com
• 8 years agoHelpfull: Yes(0) No(8)
• Wat s d crct ans??
• 8 years agoHelpfull: Yes(0) No(1)
• I guess its 443.6666667
  multiply the given small cuboids dimensions 2x3x4=24
  then multiply the cube of side 22 i.e 22x22x22=10648
  divide 10648/24 =443.6666667 so take it as 440 cubes.
• 7 years agoHelpfull: Yes(0) No(1)