the short and long hands of a clock are 4 cm and 6 cm long resp.What will be the sum of distance traveleld by their tips in 4 days.

• 2(pi)R is the formula to be used.
  min hand makes 24 rev in a day and hour hand makes 2 rev.
  total distance travelled= (2*pi*R*no of rev* 4days)+(2*pi*R*no of rev*4days)
  = (2*pi * 4*2*4 )+ (2*pi * 6*24*4)= 3820.176
  
  
• 10 years agoHelpfull: Yes(26) No(2)
• min hand is longer one. in one day it makes 24 revolutions
  hr hand makes 2 revolutions
  so, in 4 days sum of distance travelled=4*2*(22/7)*(6*24+4*2)=3821.714cms
  
• 10 years agoHelpfull: Yes(11) No(2)
• ans is 3821.7,,,
• 10 years agoHelpfull: Yes(6) No(4)
• shorthand(hr hand)revolves two rounds a day i.e d(sh)=(2*pi*4*2)*4
  minute hand revolves 24 rounds a day i.e d(mh)=(2*pi*6*24)*4
  total distance=d(sh)+d(mh)=200.96+3617.28=3818.24
• 10 years agoHelpfull: Yes(2) No(1)
• answer is 3767 cm.
• 10 years agoHelpfull: Yes(1) No(5)
• short hand-hour hand,long hand-min. hand
  in 1 day 24 hours :in 1 day hour hand hv 24 revolutions
  in 1 day 24*60 min. hand revolutions
  total distance travelled by hr hand in 4 days= 2*pi*4*24*4=768pi
  total distance travelled by min hand in 4 days= 2*pi*6*24*60*4=69120pi
  sum of distance=768pi +69120pi = 69888pi = 219448.32
• 10 years agoHelpfull: Yes(0) No(4)
• ans= 3771.42
  
  
  
  C = 2pi*r
  
  short hand makes 1 revolution every 12 hours, or 4 revolutions in 2 days. 4*2pi*4 = 32pi
  
  long hand makes 1 revolution per hour, or 48 in 2 days. 48*2pi*6 = 576pi.
  
  total: 600pi
  
  600*(22/7)
  
  1885.71 ................. fr 2 hrs..
  
  
  fr 4 hrs... 2*1885.71= 3771.42
• 9 years agoHelpfull: Yes(0) No(0)