Elitmus
Exam
Numerical Ability
Geometry
A hollow spherical shell is made of a metal of density 4.9 gm/cm3. If its internal and external diameters are 10 cm and 12 cm respectively, find the weight of the shell.
Read Solution (Total 4)
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- density=mass/volume
volume of hollow spherical=4pi/3(R^3-r^3)
so v*d=4.9*4pi/3(6^3-5^3)=4pi/3(216-125)=4.9*4pi/3(91)=4.9*4*22*13/3=1868.5
- 10 years agoHelpfull: Yes(30) No(0)
- density=mass/volume
so mass=volume*density
volume of hollow spherical=4pi/3(R^3-r^3)
so v=4pi/3(6^3-5^3)=4pi/3(216-125)=4pi/3(91)=4*22*13/3=88*13/3
now mass=v*D=88*13*4.9/3=1830.4 gm i think - 10 years agoHelpfull: Yes(11) No(8)
- mass is diff from weight.In weight ,gravitationalforce acts and weight=mass*g
- 10 years agoHelpfull: Yes(6) No(1)
- Weight= volume * density
Volume of hollow sphere= 4 pi/3(R^3-r^3) * 4.9
= 5605.6/3= 1868.5 gm - 10 years agoHelpfull: Yes(1) No(1)
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