interview Exam Numerical Ability

1) A certain street has 1000 buildings.A sign-marker is contracted to number of Houses from 1 to 1000.How many zeros will he need

2) When a number is multlipied by 13,it becomes greater to 105 by an amount with which it is

Read Solution (Total 2)

1)Ans= 192 zeros. as from 1 to 100 there are 11 zeros, from 101 to 200 there are 20 similarly for 201 to 300 and so on . and from 901 to 1000 there are 21 zeros.
total no of zeros = 11+(20*8)+21+192

2)let the no be x,
then 13x-105=x
x=35/4=8.75
10 years agoHelpfull: Yes(3) No(1)

Praneeth u r forgetting about the zeros in 101,102,103,104,105,106,107,108,109...nd so on for 201 etc
10 years agoHelpfull: Yes(2) No(0)

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