Elitmus
Exam
Logical Reasoning
Blood Relations
Chief MinisterAK,other ministers and policemen travel from one place to other in a convey.
Each of them have their own cars.There are 10 members-4 police and 6 ministers,The ministers
are AK,M,R,G,S and B
1) AK and G are scared and do not stand at the front or at the rear end of the convey
2) M is at the 9th position
3) S,B and R move one after the other and B is always between S and R.
4) AK and G are neither after nor before any minister
What are combinations possible?????
Read Solution (Total 12)
-
- ans. is 8
if police is assigned as P then
9th position is fixed and so is 10th by police becoz S B R will stick together and
AK n G have allignment of P AK P G P
so possible outcomes
P AK P G P S B R M P
P AK P G P R B S M P
P G P AK P S B R M P
P G P AK P R B S M P
S B R P AK P G P M P
R B S P AK P G P M P
S B R P G P AK P M P
R B S P G P AK P M P - 10 years agoHelpfull: Yes(48) No(7)
- ans. is 8
1P
2Ak
3P
4G
5P
6S
7B
8R
9M
10P
1 to 5 can be arranged in 2 ways n 6 to 8 in 2 ways...2*2 =4
similarly swap the 5 grp and 3 grp posn and again 4 so total 8 - 10 years agoHelpfull: Yes(10) No(4)
- 1P
2Ak
3P
4G
5P
6S
7B
8R
9M
10P
1 to 5 can be arranged in 2 ways n 6 to 8 in 2 ways...2*2 =4
similarly swap the 5 grp and 3 grp posn and again 4 so total 8 - 10 years agoHelpfull: Yes(3) No(3)
- possible outcomes
P AK P G P S B R M P
Possible arrenegement
B/W AK & G IS 2!
B/W S & R is 2!
HERE ALL POLICEMEN ARE DIFFERENT PERSON SO POSSIBILITIES IS 4!
TOTAL POSSIBILITIES IS 4!*2!*2!=96
AND ANOTHER ARRANGEMENT IS
S B R P AK P G P M P
TOTAL OUTCOMES IS 4!*2!*2!=96
FINALLY THE TOTAL POSSIBILITIES IS 96+96=192
- 10 years agoHelpfull: Yes(3) No(4)
- If we take arrangement of 4police also then it is 192 otherwise it is 8.
- 10 years agoHelpfull: Yes(2) No(3)
- ans will be 192..
4! * 2! * 2! * 2! = 192
4! is for arrangement of 4 polices.
2! is for arrangment between Ak & G.
2! is for arrangment between S,B,R [ either SBR or RBS ].
2! is for Group arrangement of SBR/RBS & P Ak P G P/PG P Ak P ie, either
P-Ak/G-P-G/Ak-P-S/R-B-R/S-M-P or S/R-B-R/S-P-Ak/G-P-G/Ak-P-M-P - 10 years agoHelpfull: Yes(1) No(8)
- s b r p1 ak p2 g p3 m p4
- 10 years agoHelpfull: Yes(0) No(5)
- PAKPGPSBRP
- 10 years agoHelpfull: Yes(0) No(3)
- p,p,ak,g,p,s,b,r,,m,p
- 10 years agoHelpfull: Yes(0) No(3)
- 1)S B R - - - - - M - :S B R arrange in 2! Ways*4 police cars in 4! Ways*in 5,6,7 position AK , G arrange in 3p2ways (6 ways)=288 ways
2)- S B R- - - -M-:S B R In 2!*police 4!*in 6,7 th position G AK arrange in 2! Way =288
3)----s B R - - M - 96 ways
4)- - - --S B R M - 96 wayss
5)---S B R - - M -not allowed
6)- -S B R - - - M -not allowed
Total ways 288+288+96+96=768 - 9 years agoHelpfull: Yes(0) No(1)
- 1) In case of AK and G group will be {P,AK,P,G,P} so this combination is 4C3 * 3!(for police) * 2!
2) For S,B,R it has 2 possible combination.
so total is (4C3*3!*2!)*(2!) *2! - 9 years agoHelpfull: Yes(0) No(1)
- If police is assigned as P then
9th position is fixed and so is 10th by police because S B R will stick together and
AK n G have alignment of P AK P G P
so possible outcomes
P AK P G P S B R M P
P AK P G P R B S M P
P G P AK P S B R M P
P G P AK P R B S M P
S B R P AK P G P M P
R B S P AK P G P M P
S B R P G P AK P M P
R B S P G P AK P M P
And there are 4 Police i.e, 4 P and they can be arranged in 4! ways.
So, 4! * 8= 32*8
= 192 ways - 9 years agoHelpfull: Yes(0) No(1)
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