Arun, Bikash and Chetakar have a total of 80 coins among them. Arun triples the no. of coins with the other by giving them some coins from his own collection. Next, Bikas repeats the same process. After this Bikash now has 20 coins . Find the no. of coins he had at the beginning?
22
20
18
24

• 20 coins
  Distribution of coins at evry stage will be as below:-
  A...B...C
  33..20...27
  11..60....9
  57...20....3
• 10 years agoHelpfull: Yes(2) No(7)
• A+B+C=80
  A+3B+3C=80
  3A+B+9C=80
  When B=20 3A+9C=60
  When B=60 A+3C=20
  When B=20 A+C=60
  So the ans is 20
• 8 years agoHelpfull: Yes(2) No(5)
• Answer=20 coins
  Distribution of coins at evry stage will be as follows:-
  A...B...C
  33..20...27
  11..60....9
  57...20....3
• 10 years agoHelpfull: Yes(1) No(7)
• A+B+C=80
  (A-Z)+3 B+3 C=80; 2 B+ 2 C=Z ........ (1)
  3(A-Z)+(3 B-Y)+9 C=80; 2(A-Z)+6 C=Y ...........(2) & 3 B-Y=20 (GIVEN)..............(3)
  from (1) & (3) put "Z" and "Y" value in (2)
  2(A-2 B-2 C)+6 C=3 B-20
  2 A-4 B-4 C+6 C=3 B-20
  2 A-7 B+2 C= -20 ........(4)
  AND
  2(A+B+C=80)
  2 A+2 B+2 C=160 ............(5)
  SUBTRACT (4) FROM (5)
  9 B=180
  B=20
• 7 years agoHelpfull: Yes(1) No(2)
• as arun triples the coins he remains with the same amount of coins he had at beginning-20
• 10 years agoHelpfull: Yes(0) No(5)