There r 2 fones huawei and sios of quantity h and s respectively.the ratio of their cost price is 3:5 and sp is 5:7.if the total profit is 50%, find h:s ?

• Sorry... It ll be 1.5*CP = SP... Thanks for pointing out d mistake... @Roshan
  
  Let CP of 2 phones be 3x nd 5x
  Let SP of 2 phones be 5y nd 7y
  (3x*h + 5x*s)*1.5 = (5y*h + 7y*s)
  4.5xh + 7.5xs = 5yh + 7ys
  7.5xs - 7ys = 5yh - 4.5xh
  s(7.5x-7y) = h(5y-4.5x)
  h/s = (7.5x-7y)/(5y-4.5x)
  We cannot determine without knowing the value of x nd y...
  
  So answer might be "Can't be determined"
• 9 years agoHelpfull: Yes(55) No(5)
• total profit for h=5h-3h=2h and profit for s=7s-5s=2s;
  so, total profit=2h+2s;
  2h+2s/3h+5s*100=50;
  so,h:s=1:1
• 9 years agoHelpfull: Yes(19) No(9)
• Let CP of 2 phones be 3x nd 5x
  Let SP of 2 phones be 5y nd 7y
  (3x*h + 5x*s)*0.5 = (5y*h + 7y*s)
  1.5xh + 2.5xs = 5yh + 7ys
  1.5xh - 5yh = 7ys - 2.5xs
  h(1.5x-5y) = s(7y-2.5x)
  h/s = (7y-2.5x)/(1.5x-5y)
  We cannot determine without knowing the value of x nd y...
  
  So answer might be "Can't be determined"
• 9 years agoHelpfull: Yes(7) No(3)
• if u dont post the questions correctly then pls dont create unneccesary confusions
• 9 years agoHelpfull: Yes(6) No(0)
• Ans:h/s=1
  let cp of 2 phn be 3x & 5x
  let sp of 2 phn be 5y & 7y
  sp=1.5cp...[Acordng to Ques]
  so, (3x*h+5x*s)*1.5=(5y*h+7y*s)
  =>4.5xh+7.5xs=5yh+7ys
  =>h/s=1....
  
• 9 years agoHelpfull: Yes(3) No(0)
• Question was CP:SP of H 3:5 cp:sp of S 5:7 CP=3+5=8 SP = 5+7 =12 12 IS 50% MORE TAN 8 ANS 3:5
• 9 years agoHelpfull: Yes(2) No(1)
• Guys ans. of ADARSH SINGH looks correct
  whats ur view about...>>>
• 9 years agoHelpfull: Yes(2) No(1)
• h:s = 1:1
  let,
  CP = Rs (3x+5x) = Rs 8x
  SP = Rs (5x+7x) = Rs 12x
  Profit = Rs 4x = 50% of CP
  Therefore h:s = 1:1
  
• 9 years agoHelpfull: Yes(2) No(1)
• let cp=x & sp=y
  so cp of h & s are 3x & 5x respectvly.
  
  and sp of h & s are 5y & 7y rsptvly
  
  total profit = (5y-3x) + (7y - 5x)
  
  %profit=50% (given)
  
  (5y-3x + 7y-5x)/8x = 50/100 //8x is total cp
  
  after solving x:y=1:1
  
  
• 8 years agoHelpfull: Yes(2) No(0)
• h:s=1
  
  If for phones of Huawei & Sios CP are 3x,5x & SP are 5x,7x respectively, then
  Total CP=3x*h+5x*s & SP=5x*h+7x*s
  Given,SP-CP=(50/100)CP
  5x*h+7x*s-(3x*h+5x*s)=(50/100)(3x*h+5x*s)
  2(2x*h+2x*s)=3x*h+5x*s
  x*h=x*s, h/s=1
• 9 years agoHelpfull: Yes(1) No(1)
• @ saraswathy- y did u take this equation
  3xh+5xs*0.5= 5xh+7xs
  Bcoz 1/2 of the cost price cant b equal to s.p.plz explain
• 9 years agoHelpfull: Yes(1) No(0)
• Since total profit is 50%
  Total CP of 2 phones is 3xh+5xs
  50% of CP = Total SP of 2 phones
  50/100(3xh+5xs) = 5yh+7ys
  So 0.5*(3xh+5xs) = 5yh+7ys
  
• 9 years agoHelpfull: Yes(1) No(0)
• @Rahul kumar
  Profit is 50%
  So Selling price ll be 150% of CP
  SP = 150/100*CP = 1.5*CP
  
• 9 years agoHelpfull: Yes(1) No(0)
• @devendra- y to take x in both in cp and sp.some difrent values will also give the ratio given in the question
• 9 years agoHelpfull: Yes(0) No(0)
• 50 % of cp = profit
  Cp+profit= sp.
  I mean to say this.
  
• 9 years agoHelpfull: Yes(0) No(0)
• Yes saraswathy. Thanku..now its perfect
• 9 years agoHelpfull: Yes(0) No(0)
• @ saraswathy hey which book u refer for apttitude?
• 9 years agoHelpfull: Yes(0) No(0)
• I refer R.S.Agarwal... @Karthik
• 9 years agoHelpfull: Yes(0) No(0)
• @SARASWATHY Can you explain why are you multiplying by 1.5 at begning.
• 9 years agoHelpfull: Yes(0) No(0)
• Thr right ans. Is 3:5
• 8 years agoHelpfull: Yes(0) No(1)