If a lies between 2 and 3, both included, and b lies between 4 and 6, both included, then what is the ratio of minimum and maximum limits of a2-b2?

• answer will be 32/7
• 9 years agoHelpfull: Yes(7) No(3)
• We have to find minimum and maximum limits of a2-b2,
  .:.a2-b2= min(a)^2-max(b)^2= 2^2-6^2 = 4-36 = -32.
  
  .:.a2-b2 = max(b)^2- min (a)^2 = 3^2 - 4^2 = 9-16 = -7
  
  Ratio = -32/-7 = 32/7
• 6 years agoHelpfull: Yes(4) No(1)
• 1-2 is correct
• 9 years agoHelpfull: Yes(2) No(3)
• hw it is please explain?
• 9 years agoHelpfull: Yes(2) No(0)
• (a2 - b2)min = a2min - b2max = 22 - 62 = -32.
  (a2 - b2)max = a2max - b2min = 32 - 42 = -7.
  Hence the required ratio = 32:7.
• 7 years agoHelpfull: Yes(2) No(3)