Using recursion print numbers of an array.

• int print(int a[],int i,int n){
  if(i
• 10 years agoHelpfull: Yes(3) No(0)
• void print(int arr[], int n, int i){
  if(i
• 9 years agoHelpfull: Yes(1) No(0)
• simple java code...
  
  import java.util.Scanner;
  
  class RecArray
  {
  private static int i=0;
  static void print(int A[])
  {
  if(i==A.length)
  {
  return;
  }
  System.out.println(A[i]);
  i++;
  print(A);
  }
  public static void main(String[] args)
  {
  System.out.print("nEnter the no. of elements : ");
  Scanner sc = new Scanner(System.in);
  int n = sc.nextInt();
  int A[] = new int[n];
  System.out.println("nEnter the array elements :");
  for(int a=0;a
• 9 years agoHelpfull: Yes(1) No(0)
• #include
  #include
  
  void fun(int a[],int,int);
  
  int main()
  {
  int s;
  printf("enter size of array");
  scanf("%d",&s);
  
  int a[s],i,temp=0;
  
  printf("enter nos of arrayn");
  
  for(i=0;i0)
  {
  
  printf("%dn",a[index]);
  index++;
  size--;
  fun(a,size,index);
  
  }
  
  return;
  
  
  }
• 8 years agoHelpfull: Yes(0) No(0)
• #include
  using namespace std;
  void rec(int a[],int n)
  {
  if(n==0)
  return;
  else
  {
  cout
• 8 years agoHelpfull: Yes(0) No(0)
• #include
  #define MAX 100
  int fun(int p[],int);
  int main()
  {
  int a[MAX],i,n;
  printf("enter the values of n: ");
  scanf("%d",&n);
  printf("nenter the array elements: ");
  for(i=0;i
• 8 years agoHelpfull: Yes(0) No(0)