Campus
Maths Puzzle
Numerical Ability
find The value
5-4=23
8-1=63
6-16=32
9-9=78
3-9=6
3-81=??
Read Solution (Total 6)
-
- the seq is
a-b=(a^2)-(b^(1/2))
so, answer= 9-9=0 - 10 years agoHelpfull: Yes(3) No(1)
- 5-4=23 like that 5^2-2(square root of 4 )=23
8^2-1=63
6^2-4=32 and so on ....
so last 3^2 - 9(square root of 81)=0 answer
- 10 years agoHelpfull: Yes(0) No(1)
- 5*5-(4^0.5)=23
similarly
8*8-(1^0.5)=63
hence
3*3-(81^0.5)=0 - 10 years agoHelpfull: Yes(0) No(1)
- 5^2-(4^1/2)=23
similarly
8^2-(1^1/2)=63
hence
3^2-(81^1/2)=0
Answer: 0 - 10 years agoHelpfull: Yes(0) No(0)
- 5^2 - (4^(1/2)) =23
8^2 - (1^(1/2)) =63
6^2 - (16^(1/2)) =32
9^2 - (9^(1/2)) =78
3^2 - (9^(1/2)) =6
so answer is
3^2 - (81^(1/2)) =0
- 10 years agoHelpfull: Yes(0) No(0)
- 3^2-81^(1/2)=0
- 10 years agoHelpfull: Yes(0) No(0)
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