A type of mixture is prepared by mixing brand at Rs.9 a kg with brand B at Rs.4 a kg.If a mixtue is worth rupees 7 a kg,how many kgs of brand A are needed to make 40 kgs of the mixture?

• 9 4
  7
  (7-4)=3 (9-7)=2
  3*40/5=24
• 10 years agoHelpfull: Yes(19) No(0)
• 9 4
  7
  (7-4) 3 2 (9-7)
  
  thus ratio would be 3:2
  and thus 3x+2x=40
  so x=8 and 3x=24.
  thus A type of mixture would be of 24 kg.
• 10 years agoHelpfull: Yes(5) No(0)
• 60 kgs,in order to maintain the ratio 3:2 between A:B
• 10 years agoHelpfull: Yes(2) No(3)
• answer should be 16
• 10 years agoHelpfull: Yes(2) No(2)
• ratio is 3:2 which is to be shared by 40kgs.therefore no .of kgs brand A to be mixed is 24kgs
  
• 10 years agoHelpfull: Yes(1) No(0)
• 24 kg
  9-7=2
  7-4=3
  ratio of A:B=3:2
  so 24+16=40
• 10 years agoHelpfull: Yes(1) No(1)
• 7= (9*a+4*b)/a+b
  9a +4b =7a+7b
  9a-7a=7b-4b
  2a=3b
  a/b=3:2
  the required amount of brand A is (3/5*40)=24 kg.
  
• 8 years agoHelpfull: Yes(0) No(0)
• Let A is x kg
  9*x + 4 ( 40 - x ) = 7 * 40
  after solving x== 24
• 8 years agoHelpfull: Yes(0) No(0)