The greatest number that will divide 63, 138 and 228 so as to leave the same remainder in each case:

• HCF of ((138-63),(228-138),(228-63))
  HCF of (75,90,165)
  75=3*5*5
  90=2*3*3*5
  165=3*5*11
  ans=3*5=15
• 10 years agoHelpfull: Yes(19) No(0)
• 138-63=75
  228-138=90
  hcf(90,75)=15 Ans.
• 10 years agoHelpfull: Yes(2) No(8)
• The greatest number = H.C.F of (138-63), (228-138), (228-63)
  H.C.F of 75, 90, 165 = 15.
  15 is the greatest number.
• 9 years agoHelpfull: Yes(1) No(0)
• we have to find GCM of (228-138), (138-63), (228-63),. i.e G.C.M of 90,75,165 which is '15'
• 9 years agoHelpfull: Yes(0) No(0)
• Hcf of (228-138) , (228-63) , (138-63)
  Hcf of (90, 165 , 75) as
  90 = 2×3××3×5
  165 = 3×5×11
  75= 3×5×5
  Hcf of (90,165,75) is 3×5 = 15
  ANS 15
• 7 years agoHelpfull: Yes(0) No(0)