Population of a village is eight thousand. If 6% men and 10% women are added, population becomes 8,600, then the number of men in the village was:

• x=no of men at beginning,
  y=no of women at beginning,
  .06x+0.1y=600;(its 8600-8000)
  x+y=8000;
  solve these eqn ,
  we can get x=5000;y=3000;
  in the beginning there were 5000 men.
• 10 years agoHelpfull: Yes(25) No(5)
• take x male then 8000-x=female
  so x*106/100 + (8000-x)*110/100 =8600
  by solving we get x=5000(men)
  
• 10 years agoHelpfull: Yes(10) No(5)
• using mixtures : there is increase in 6% men and 10% women
  i.e 3 : 5
  therefore number of 6% mens will be: (3/8)*8000=3000
  6%----> 3000
  100%----> ?
  therefore by cross multiplying ans is 5000.
• 7 years agoHelpfull: Yes(8) No(3)
• using mixture and alligation
  8000×106/100=8480
  8000×110/100=8800
  
  
  male 8400 female 8800
  8600
  
  200:120
  5:3
  
  Number of males in the village
  =5/8×8000=5000
• 7 years agoHelpfull: Yes(3) No(2)
• 5000 men +3000 women
• 10 years agoHelpfull: Yes(2) No(6)
• 5*1000=5000
• 6 years agoHelpfull: Yes(1) No(2)