If 4 consecutive letters are selected at random from the English alphabet, then the probability that one of the letters is a vowel is ?
13/23
16/23
11/23
17/23

• Total no. of ways of selecting 4 consecutive letters => 23 [Like abcd, bcde, efgh,..etc]
  No. of ways of having one is a vowel => abcd, bcde, cdef, defg, efgh, fghi, ghij, hijk, ijkl, lmno, mnop, nopq, opqr, rstu, stuv, tuvw, uvwx...
  = 17
  P(one of letter is vowel) = 17/23
  
  Ans : 17/23
• 9 years agoHelpfull: Yes(70) No(2)
• By taking 4 consecutive letters,like abcd, bcde,.. we can make 23 ways.
  
  Note that except a, x, y ,z all other alphabet comes in 4 above combinations.
  Hence 4 vowels [except a ] ie, e,i,o,u repeats 4 times.
  4*4=16
  and a word comes once
  so total 17
  hence ans is 17/23
• 9 years agoHelpfull: Yes(12) No(0)
• Total no. of ways of selecting 4 consecutive letters from english alphabet={abcd,bcde,cdef,defg,efgh,fghi,ghij,hijk,ijkl,jklm..etc}=total 23 ways
  
  From the above list only 17 ways containing only one vowel
  so
  P(one of the letter is vowel)=17/23
• 9 years agoHelpfull: Yes(3) No(1)
• answer is 17/23
• 9 years agoHelpfull: Yes(0) No(0)
• there are 23 ways to select consecutive letters, i.e. abcd, bcde,cdef,defg and so on. and out of which , 17 contains one letter as vowel, so probability is 17/23.
• 6 years agoHelpfull: Yes(0) No(0)