Let y={(1+ai)/(b-i)}^x,where a,b,x & y are integers.It is known that x is an even number greater than 100 but not divisible by 4.Which of the following statements will always the true?
(a)both a & b are +ve but nt equal
(b)both a & b are -ve are nt equal
(c)both a&b are prime numbers and nt equal
(d)both a&b can take any values as long as they are equal

• Y = (1+ai/b-i)^x .. X is even number but not divisiable by 4, so x=2*odd no ..
  Y= (1-a^2+2ai/b^2-1-2bi)^odd number .. (a+ix)^odd_number will always have a part containing (i) .. So dt will not be an integer .. So by check n trying option d , ..this will be the ans .. Cause nevegative whole numbers are also integers
• 10 years agoHelpfull: Yes(3) No(4)