Chief MinisterAK,other ministers and policemen travel
from one place to other in a convey.
Each of them have their own cars.There are 10
members-4 police and 6 ministers,The ministers
are AK,M,R,G,S and B
1) AK and G are scared and do not stand at the front or
at the rear end of the convey
2) M is at the 9th position
3) S,B and R move one after the other and B is always
between S and R.
4) AK and G are neither after nor before any minister
5)There is a Police between A&R.
What are combinations possible?????

• S B R P AK P G P M P
• 9 years agoHelpfull: Yes(29) No(5)
• ans=8
  as per condition
  1) S, B, R, P, AK, P, G, P, M, P.(WHERE P IS FOR POLICE)
  2) R, B, S, P, AK, P, G, P, M, P.
  3) S, B, R, P, G, P, AK, P, M, P.
  4) R, B, S, P, G, P, AK, P, M, P.
  5) P, AK, P, G, P, S, B, R, M, P.
  6) P, AK, P, G, P, R, B, S, M, P.
  7) P, G, P, AK, P, S, B, R, M, P.
  8) P, G, P, AK, P, R, B, S, M, P.
  
• 9 years agoHelpfull: Yes(23) No(18)
• S B R P AK P G P M P
  S B R P G P AK P M P
  R B S P AK P G P M P
  R B S P G P AK P M P
  4 combinations
• 9 years agoHelpfull: Yes(16) No(18)
• 2 sol possible
• 9 years agoHelpfull: Yes(14) No(2)
• there can be 8 combinations....!!
  
  P G P AK P R B S M P
  P G P AK P S B R M P
  P AK P G P R B S M P
  P AK P G P S B R M P
  S B R P AK P G P M P
  S B R P G P AK P M P
  R B S P AK P G P M P
  R B S P G P AK P M P
• 9 years agoHelpfull: Yes(13) No(4)
• S B R P AK P G P M P
  P G P AK P R B S M P
• 9 years agoHelpfull: Yes(10) No(0)
• 6 combinations
• 9 years agoHelpfull: Yes(5) No(7)
• two
  S,B,R,P,AK,P,G,P,M,P
  P,G,P,AK,R,B,S,P,M,P
• 9 years agoHelpfull: Yes(4) No(2)
• 
  It is the only correct option
  : S B R P AK P G P M P
  
  see points 3) and 5)
  
• 9 years agoHelpfull: Yes(4) No(2)
• 5 combinations
  ak p r b s p g p m p
  s b r p ak p g p m p
  g p s b r p ak p m p
  p p g p ak p r b s m
  p g p ak p r b s m p
  5 combinations
• 9 years agoHelpfull: Yes(3) No(17)
• s b r p ak p g p m p
  g p s b r p ak p m p
  p p g p ak p r b s m
  p g p ak p r b s m p
  4 combinations
• 9 years agoHelpfull: Yes(3) No(7)
• Here 8 possibilities is the right option because,first we take +ve conditions(2,3,5) and then -ve conditions(1,4).m possible only once.In 3 rd condition B fixed to one position.in the same condition S,R can vary in 2 positions.A can give in one position and also police in between a&R also one position.In 1st condition for AK,G we can arrange 2 positions(AK,G)(G,Ak).finally Police can arrange in 2 positions.assume this as one by one for given pattern.P,S,B,R,P,A,AK,M,G,P.so,1*1*2*1*2*2.
  so,final ans is 8
• 9 years agoHelpfull: Yes(3) No(2)
• 8 possible combinations
  
• 9 years agoHelpfull: Yes(2) No(3)
• ak p r b s p g p m p
  s b r p ak p g p m p
  g p s b r p ak p m p
  3 combinations
  
• 9 years agoHelpfull: Yes(2) No(14)
• as s,b,r move one after other in a sequence and after them only ak an g can move as thay have ploice before , after and between them. m is fixed at 9th place. so, only one case is valid......that is:
  s b r p ak p g pm p.............here p= police
• 9 years agoHelpfull: Yes(2) No(1)
• there will be 8 combinations
  s b r p ak p g p m p
  s b r p g p ak p m p
  r b s p ak p g p m p
  r b s p g p ak p m p
  p ak p g p s b r m p
  p ak p g p r b s m p
  p g p ak p s b r m p
  p g p ak p r b s m p
  
• 9 years agoHelpfull: Yes(2) No(3)
• what are the no of possible combination??
  option were 1)3
  2) 4
  3) 5
  4) 6
• 9 years agoHelpfull: Yes(1) No(3)
• @ aditi
  ur first combination is not correct as
  ak cannot be at first place
• 9 years agoHelpfull: Yes(1) No(1)
• 2 combinations
  P M S B R P AK P G P
  P M P G P AK P R B S
• 9 years agoHelpfull: Yes(1) No(1)
• There are 8 combinations possible.
  Combination=Selection
  
  Let us first eliminate the positions Arvind and G cannot occupy.
  These will be 1,8,9 and 10.
  1 and 10 due to the 1st condition
  8 and 9 due to the 4th and 2nd conditions respectively
  
  S-B-R can occupy only 3 consecutive positions.
  This can be 1-2-3, 2-3-4, 3-4-5, 4-5-6, 5-6-7 or 6-7-8
  
  If we select 1-2-3, the 4th position becomes unavailable for Arvind/G owing to condition 4. Now, 3 positions available(5,6,7) for 2 ministers Arvind and G. This will be 3C2=3
  
  If we select 2-3-4, the 5th position becomes unavailable for Arvind/G. Now, only 2 positions(6,7) available for 2 ministers. This will be 2C2=1
  
  If we select 3-4-5, the 2nd and 6th positions become unavailable. Now only 1 position(7) available for 2 ministers.
  Similarly, for 4-5-6, the 3rd and 7th positions become unavailable. Now also only 1 position(2) available for 2 ministers.
  
  If we select 5-6-7, the 4th position becomes unavailable for Arvind/G. Now, only 2 positions(2,3) available for 2 ministers. This will be 2C2=1
  
  If we select 6-7-8, 5th position becomes unavailable. Now 3 positions(2,3,4) available for Arvind/G. This will be 3C2=3
  
  Thus, the total number of combinations=3C2+2C2+2C2+3C2=3+1+1+3=8
  
• 8 years agoHelpfull: Yes(1) No(1)
• ans=2
  8 combinations
  1) S, B, R, P, AK, P, G, P, M, P.(WHERE P IS FOR POLICE)
  2) R, B, S, P, AK, P, G, P, M, P.
  3) S, B, R, P, G, P, AK, P, M, P.
  4) R, B, S, P, G, P, AK, P, M, P.
  5) P, AK, P, G, P, S, B, R, M, P.
  6) P, AK, P, G, P, R, B, S, M, P.
  7) P, G, P, AK, P, S, B, R, M, P.
  8) P, G, P, AK, P, R, B, S, M, P.
  and only 2 satisfy condition five 1 & 8 so answer is 2.
• 8 years agoHelpfull: Yes(1) No(0)
• Total 6 combinations
  S B R P AK P G P M P
  S B R P G P AK P M P
  R B S P AK P G P M P
  R B S P G P AK P M P
  P G P AK P R B S M P
  P G P AK P S B R M P
• 8 years agoHelpfull: Yes(1) No(2)
• Two combination can be form
  Pgp ak prbsmp
  Sbrp ak pgpmp
  Where p =policemen
• 8 years agoHelpfull: Yes(1) No(0)
• s ,b,r,police,AK,police,police,G,police,M,police
• 9 years agoHelpfull: Yes(0) No(12)
• @G.VEERANJANEYA VARA PRASAD
  in ur combination there are 5 police but in given que there are only 4
• 9 years agoHelpfull: Yes(0) No(3)
• only one.. S B R P AK P G P M P
• 9 years agoHelpfull: Yes(0) No(3)
• S,B,R,P,AK,P,G,P,M,P
• 9 years agoHelpfull: Yes(0) No(1)
• S B R P AK P G P M P
• 9 years agoHelpfull: Yes(0) No(1)
• all are elitmus 13 july ques
  
• 9 years agoHelpfull: Yes(0) No(1)
• There are 8 conditions as shown by @RAHUL KUMAR
• 9 years agoHelpfull: Yes(0) No(1)
• please tell the right answer...
  
  
• 9 years agoHelpfull: Yes(0) No(2)
• 4 combinations possible
• 9 years agoHelpfull: Yes(0) No(1)
• P S B R P AK P G M P
  P S B R P AK P G M P
  S B R P AK P G P M P
  S B R P G P AK P M P
• 9 years agoHelpfull: Yes(0) No(2)
• 6+2=8 so 8 combination
  
• 9 years agoHelpfull: Yes(0) No(1)
• 1-P
  2-G
  3-P
  4-AK
  5-P
  6-R
  7-B
  8-S
  9-M
  10-P
  
• 9 years agoHelpfull: Yes(0) No(1)
• Plz send me study materials of DI for elitmus.. Sarojanikumbar@gmail.com. thank u in advance
• 9 years agoHelpfull: Yes(0) No(1)
• Plz send me study materials of DI for elitmus.. Sarojanikumbar@gmail.com. thank u in advance
• 9 years agoHelpfull: Yes(0) No(1)
• 12 combinations
  S B R P A G P P M P (WHERE A IS AK)
  R B S P A G P P M P
  S B R P G A P P M P
  R B S P G A P P M P
  P S B R P A G P M P
  P R B S P A G P M P
  P S B R P G A P M P
  P R B S P G A P M P
  P P S B R P A G M P
  P P R B S P A G M P
  P P S B R P G A M P
  P P R B S P G A M P
• 9 years agoHelpfull: Yes(0) No(6)
• 2 solution possible
  SBRPAPGPMP
  PGPAPRBSMP
  bcz according to 5th condition there is always one policemn between a and r.
• 8 years agoHelpfull: Yes(0) No(1)
• there is only 1 possibility
  S D R P AK P G P M P because there shd be only 1 policeman between ak and r..... all other possibilities violates this rule
• 8 years agoHelpfull: Yes(0) No(1)
• There are 4 options possible ,
  according to point 5 there could be only one police between Ak and R, and according to 3 SBR will be one after another and their order could change in two ways. one more point we have to focus that their must be one police adjacent to Ak and G both so here is the arrangements given below
  
  
  P G P AK P R B S M P
  P G P Ak P R S B M P
  these two arrangements given above by changing the order of rbs and rsb.by maintaining (Ak P R) same on both
  S B R P AK P G P M P
  B S R P AK P G P M P
  again by changing the order of SBR and BSR but (AK P R)would be same
  
  
  P G P AK P R B S M P
  P G P Ak P R S B M P
  S B R P AK P G P M P
  B S R P AK P G P M P 4 arrangement according to me :)
  
• 8 years agoHelpfull: Yes(0) No(1)
• S B R P1 AK P2 G P3 M P4
• 7 years agoHelpfull: Yes(0) No(1)
• There are 8 combinations possible.
  Let us first eliminate the positions Arvind and G cannot occupy.
  These will be 1,8,9 and 10.
  1 and 10 due to the 1st condition , 8 and 9 due to the 4th and 2nd conditions respectively.
  
  S-B-R can occupy only 3 consecutive positions. This can be 1-2-3, 2-3-4, 3-4-5, 4-5-6, 5-6-7 or 6-7-8.
  If we select 1-2-3, the 4th position becomes unavailable for Arvind or G owing to condition 4. Now, 3 positions available(5,6,7) for 2 ministers Arvind or G. This will be 3C2=3.
  If we select 2-3-4, the 5th position becomes unavailable for Arvind or G. Now, only 2 positions(6,7) available for 2 ministers. This will be 2C2=1.
  If we select 3-4-5, the 2nd and 6th positions become unavailable. Now only 1 position (7) available for 2 ministers. Similarly, for 4-5-6, the 3rd and 7th positions become unavailable. Now also only 1 position (2) available for 2 ministers.
  If we select 5-6-7, the 4th position becomes unavailable for Arvind or G. Now, only 2 positions(2,3) available for 2 ministers. This will be 2C2=1.
  If we select 6-7-8, 5th position becomes unavailable. Now 3 positions(2,3,4) available for Arvind/G. This will be 3C2=3.
  Thus, the total number of combinations=3C2 +2C2 +2C2+3C2 = 3 + 1 + 1 + 3 = 8.
• 5 years agoHelpfull: Yes(0) No(0)