A number F completely divides this expression (40^240+32^240-3^240-5^240).
what is the value of F?

• 10
  
  2^(240*3)*5^240+2^(240*5)-3^240-5^240
• 10 years agoHelpfull: Yes(0) No(1)
• 2 net result is definately a even
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• F= 35*37= 1295
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• div by 5.
  40^240=8^240*5^240 so expression becomes 5^240(8^240-1)+32^240-3^240.
  Now 5 to the power something will always have a no ending with 5. and that no product with odd no will again have 5 in the end. So 5^240(8^240-1) is divisible by 5. Again 32 to the power even - 3 to power even= no ending with 5. So the whole expression is divisible by 5.
  
• 10 years agoHelpfull: Yes(0) No(0)