A is 20 percent more efficient than B If the two persons can complete a piece of work in 60

let A completes his work in x days and B completes in y days

A's one day work = 1/x
B's one day work = 1/y

since A is 20% more efficient than B so

1/x = ((1/y)+(20% of 1/y))
y=1.2x

both can complete the work in 60 days, now we have

(1/x)+(1/y)=(1/60)
=> (1/x) + (1/1.2x) = 1/60
=> x = 110 days

so, A can complete his work in 110days
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assume both r equally efficient then each can cmplete the work in 120 days .
but if A is 20% more efficient then A can complete the work in (120-20% of 120)
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Let B's 1 day work is x
Then A's 1 day work will be 6x/5

(A+B)'s 1 day work = (A's 1 day work + B's 1 day work) = 1/60
x+6x/5 = 1/60
x= 1/132

Therefore A's 1 day work = 1/110
or A's 110 days work = 1
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A is 20 percent more efficient than B. If the two persons can complete a piece of work in 60 days, in how many days A working alone can complete the work?