A is 20 percent more efficient than B. If the two persons can complete a piece of work in 60 days, in how many days A working alone can complete the work?

• 110 days
  
  A is 20% more efficient than B
  Ratio of time taken by A to B = 100 : 120 = 5:6
  
  Let the time taken by them working alone be 5x and 6x respectively.
  Together they can finish the work in 60 days.
  
  (5x*6x)/(5x+6x) = 60
  30x^2/11x = 60
  x = 2*11 = 22
  
  A alone can finish the work in = 5x = 110 days
  
• 9 years agoHelpfull: Yes(2) No(0)
• let A completes his work in x days and B completes in y days
  
  A's one day work = 1/x
  B's one day work = 1/y
  
  since A is 20% more efficient than B so
  
  1/x = ((1/y)+(20% of 1/y))
  y=1.2x
  
  both can complete the work in 60 days, now we have
  
  (1/x)+(1/y)=(1/60)
  => (1/x) + (1/1.2x) = 1/60
  => x = 110 days
  
  so, A can complete his work in 110days
  
• 9 years agoHelpfull: Yes(2) No(0)
• 96
  assume both r equally efficient then each can cmplete the work in 120 days .
  but if A is 20% more efficient then A can complete the work in (120-20% of 120)
• 9 years agoHelpfull: Yes(0) No(1)
• Let B's 1 day work is x
  Then A's 1 day work will be 6x/5
  
  (A+B)'s 1 day work = (A's 1 day work + B's 1 day work) = 1/60
  x+6x/5 = 1/60
  x= 1/132
  
  Therefore A's 1 day work = 1/110
  or A's 110 days work = 1
• 9 years agoHelpfull: Yes(0) No(0)
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• 9 years agoHelpfull: Yes(0) No(0)