find the day of the week on 25th december 1995

• 1600 years - 0 odd days
  300 years - 1 odd day
  94 years - 5 odd days
  1995'th year - 2 odd days
  
  1+5+2 / 7 = 1 odd days
  
  Monday.
• 10 years agoHelpfull: Yes(16) No(6)
• Last two digit of the year= 95
  95 divided by 4 =23 as quotient.
  Code of the dec month =6 [ Code of months - ( JAN : 1 , FEB : 4 , MAR : 4 , APR : 0 , MAY : 2 , JUNE : 5 , JULY :0 , AUG : 3 , SEP : 6 , OCT : 1 , NOV : 4 , DEC : 6 )]
  Given Date =25
  
  ADD : 95 + 23 + 6 + 25 =149
  149 / 7 = 2 as a remainder i.e. Tuesday.
  [ MON : 1 , TUES : 2, WED : 3 ,THURS : 4 , FRI : 5 , SAT : 6 , SUN : 0]
  So, ans is TUESDAY.
• 10 years agoHelpfull: Yes(9) No(12)
• tuesday.
  for 1900 yrs-15 odd days.
  for 94yrs-6 odd days.
  upto dec 25-51 odd days.
  15+6+51=72
  72/7=rem 2
  if rem=0,sunday
  1=monday,2=tuesday n so on.
  so ans is tuesday.
• 10 years agoHelpfull: Yes(3) No(6)
• 1600 year-0 odd days
  300 year-(5*3)/7=1 odd days
  94 year (23*2+71)/7=5 odd days
  1995th year -(31+28+31+30+31+30+31+31+30+31+30+25)/7=2 odd days
  
  (1+5+2)/7=1 odd days
  monday
• 10 years agoHelpfull: Yes(2) No(2)
• 25-DEC-2015
  
  day codes --> Sun - 0, Mon-1, Tue-2, Wed-3, Thu-4. Fri-5, Sat-6.
  
  month codes --> Jan-0, Feb-3, Mar-3, Apr-6, May-1, Jun-4, Jul-6 , Aug-2, Sep-5, Oct-0, Nov-3, Dec-5.
  
  Century Codes --> 1600-1699 -- 6
  1700-1799 -- 4
  1800-1899 -- 2
  1900-1999 -- 0
  2000-2099 -- 6
  
  step-1:
  take DATE and LAST TWO DIGITS OF YEAR then add those two numbers.
  
  25+95=120
  
  step2:
  
  Divide last two digits of the year with 4 and then take quotient into consideration.
  
  95/4=23(quotient).
  
  step3;
  
  step1 + step2 + cetury code + month code
  
  120+23+0+5=148
  
  step4:
  
  divide the resultant value with 7 and then take the remainder into consideration
  
  148/7=1(remainder)
  
  
  1 means monday
  
  
  
  
  
  
  
  
• 9 years agoHelpfull: Yes(2) No(0)
• 1900-1999=0 odd days.
  december=5
  25(date)+95(last 2 value of year)=120
  divide last 2 digits of year by 4 and take quotient value alone.
  95/4=23
  # 23+120=143
  143+5(month code of dec)=148
  divide the final answer by 7.
  148/7=21+1
  ANs:monday.
  
• 10 years agoHelpfull: Yes(1) No(2)
• @Sneha, Acc. to ur concept, the ans of my another ques. " Ques. June 30, 2004 is wednesday. What is June 30, 1974? " should be Monday (as 74+18+30+5 = 127, and 127 / 7 = 1) ...But the Ans is not Monday...Ans is Sunday............Now fix it....!!
• 10 years agoHelpfull: Yes(1) No(2)
• what is month code in last(priya) solution?
• 10 years agoHelpfull: Yes(0) No(0)
• for 1600 years - 0 odd day
  
  for 300 years - 1 odd day
  
  94 years - (94/4) gives 23 leap year & 71 normal year
  hence (23*2 + 71*1) /7 = 5 odd days....{leap year has 2 odd year hence 23*2 & normal year has 1 odd day hence 71*1 }
  
  1995th year - (365-6)= 359/7= 2 odd days {as we are finding for 25th December and 1995th year has 365 days hence to find 25th of December we would minuus 6 from total days that id 365}.
  
  add all the odd days and divide from 7 the accordingly:-
  
  1+5+2 / 7 = 1 odd day
  
  hence for 1=Monday is right answer
• 9 years agoHelpfull: Yes(0) No(0)
• consider last two digits of year i.e. 95
  95/4=23
  consider date 26
  the code of months is 0(jan),3(feb),3,6,1,4,6,2,5,0,,3,5(dec)
  so the code of december is 5
  add all values i.e. 95+23+26+5=148
  then 148 % 7=1(remainder)
  codes of days is 0(sun),1(mon),2,3,4,5,6(sat)
  so the day is MONDAY.
• 9 years agoHelpfull: Yes(0) No(0)