12 years ago the ages of A and B were in the ratio 15:13. 19 years from now, the ratio of their ages will be 23:22. What is the sum of their ages at present?

• ans:52
  ratio of their ages 12 years ago=15:13
  therefore at present their ages will be=15x+12,13x+12
  given after 19 yrs from now ratio of their ages will be 23:22
  so,
  15x+12+19/13x+12+19=23/22;
  15x+31/13x+31=23/22;
  22(15x+31)=23(13x+31);
  x=1
  present age of A= 15x+12= 27
  present age of B=13x+12= 25
  sum= 27+25= 52
• 10 years agoHelpfull: Yes(4) No(0)
• 15x+12+19/13x+12+19=23/22
  x=1
  A present age=15x+12=27
  B present age=13x+12=25
  sum of their present ages=52
• 10 years agoHelpfull: Yes(0) No(0)
• Let present age of A= x
  and " " " B= y
  12 years ago
  age of A= x-12
  age of B= y-12
  ratio of there age's ==> (x-12)/(y-12)= 15/13
  ==> 15y-13x=24
  ==> y=(24+13x)/15 ----eq.(1)
  19 years from now
  age of A= x+19
  age of B= y+19
  ratio==> (x+19)/(y+19)=23/22
  ==> 22x-23y=19 ---eq.(2)
  putting eq.(1) in eq.(2), we get
  x=27
  y=25
  so sum of der present age's = x+y= 52
• 10 years agoHelpfull: Yes(0) No(1)